我有一张表EmpDetails：
DeptID EmpName Salary
Engg Sam 1000
Engg Smith 2000
HR Denis 1500
HR Danny 3000
IT David 2000
IT John 3000
我需要进行查询，找出每个部门的最高工资。
答案 0 :(得分：29)
简短问题：
SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID
答案 1 :(得分：21)
假设SQL Server 2005 +
WITH cteRowNum AS (
SELECT DeptID, EmpName, Salary,
DENSE_RANK() OVER(PARTITION BY DeptID ORDER BY Salary DESC) AS RowNum
FROM EmpDetails
)
SELECT DeptID, EmpName, Salary
FROM cteRowNum
WHERE RowNum = 1;
答案 2 :(得分：5)
Select empname,empid,Sal,DeptName from
(Select e.empname,e.empid,Max(S.Salary) Sal,D.DeptName, ROW_NUMBER() Over(partition by D.DeptName order by s.salary desc) Rownum
from emp e inner join Sal S
on e.empid=s.empid
inner join Dept d on e.Deptid=d.Deptid
group by e.empname,e.empid,D.DeptName,s.Salary
) x where Rownum = 1
答案 3 :(得分：3)
使用以下问题：
select employee_name,salary,department_id from emp where salary in(select max(salary) from emp group by department_id);
答案 4 :(得分：3)
SELECT empName,empDept,EmpSalary
FROM Employee
WHERE empSalary IN
(SELECT max(empSalary) AS salary
From Employee
GROUP BY EmpDept)
答案 5 :(得分：3)
如果您想要显示其他参数以及DeptId和Salary，例如EmpName，EmpId
SELECT
EmpID
, Name,
, Salary
, DeptId
FROM Employee
where
(DeptId,Salary)
in
(select DeptId, max(salary) from Employee group by DeptId)
答案 6 :(得分：2)
这是ORACLE的最佳解决方案：
Select * from (select customerid, city, freight,
row_number() over (partition by customerid order by freight desc) Row_Number from
(select orders.orderId, customers.CUSTOMERID, customers.city, orders.FREIGHT from orders inner join customers on orders.customerid = customers.customerid where customers.country='Germany' order by customers.customerid, orders.freight desc)
order by customerid, freight desc) where Row_Number<=2;
注意这里我使用了partition by子句来标记行号，这主要是因为我们需要根据客户ID对记录进行分组。我在这里使用了两个内部查询。最内部的查询是给出根据客户ID和降低成本顺序排序的视图。现在我们需要获得前两个记录，所以首先我们需要命名它们然后我们需要根据rownum过滤它们。二级查询是根据客户ID标记rownum。最终查询将根据rownum过滤结果。对于每个分区。
答案 7 :(得分：2)
***
> /*highest salary by each dept*/
***
select d.Dept_Name,max(e.salary)
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
group by d.Dept_Name
select distinct e.d_id,d.Dept_Name
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
select e.salary,d.Dept_Name,d.Dept_Id
from emp_details as e join Dept_Details as d
on e.d_id=d.Dept_Id
/////simplest query for max salary dept_wise////
答案 8 :(得分：2)
SELECT D.DeptID, E.EmpName, E.Salary
FROM Employee E
INNER JOIN Department D ON D.DeptId = E.DeptId
WHERE E.Salary IN (SELECT MAX(Salary) FROM Employee);
答案 9 :(得分：2)
SELECT
DeptID,
Salary
FROM
EmpDetails
GROUP BY
DeptID
ORDER BY
Salary desc
答案 10 :(得分：2)
使用以下命令;
SELECT A.*
FROM @EmpDetails A
INNER JOIN ( SELECT DeptID ,
MAX(salary) AS salary
FROM @EmpDetails
GROUP BY DeptID
) B ON A.DeptID = B.DeptID
AND A.salary = B.salary
ORDER BY A.DeptID
答案 11 :(得分：2)
如果部门，工资和员工姓名在同一个表中，这将有效。
select ed.emp_name, ed.salary, ed.dept from
(select max(salary) maxSal, dept from emp_dept group by dept) maxsaldept
inner join emp_dept ed
on ed.dept = maxsaldept.dept and ed.salary = maxsaldept.maxSal
有没有比这更好的解决方案？
答案 12 :(得分：2)
SELECT Employee_ID
, First_name
, last_name
, department_id
, Salary
FROM (SELECT Employee_ID
, First_name
, last_name
, department_id
, Salary
, MAX(salary) OVER (PARTITION BY department_id) dept_max_sal
FROM EMPLOYEES) AS Emp
WHERE salary = dept_max_sal;
答案 13 :(得分：2)
select a.*
from EmpDetails a
inner join
(
select DeptID,max(Salary) as Salary
from EmpDetails group by DeptID
)b
on a.DeptID = b.DeptID and a.Salary = b.Salary
答案 14 :(得分：2)
WITH cteRowNum AS (
SELECT DeptID, EmpName, Salary,
ROW_NUMBER() OVER(PARTITION BY DeptID ORDER BY Salary DESC) AS RowNum
FROM EmpDetails
)
SELECT DeptID, EmpName, Salary,Rownum
FROM cteRowNum
WHERE RowNum in(1,2);
答案 15 :(得分：2)
SELECT empname
FROM empdetails
WHERE salary IN(SELECT deptid max(salary) AS salary
FROM empdetails
group by deptid)
答案 16 :(得分：2)
select
d.DeptID,
max(e.Salary)
from
department d
inner join employees e on d.DeptID = e.DeptID
group by
d.DeptID
答案 17 :(得分：1)
这是一种在任何版本的SQL上获取最大值和名称的方法。
测试数据：
CREATE TABLE EmpDetails(DeptID VARCHAR(10), EmpName VARCHAR(10), Salary DECIMAL(8,2))
INSERT INTO EmpDetails VALUES('Engg','Sam',1000)
INSERT INTO EmpDetails VALUES('Engg','Smith',2000)
INSERT INTO EmpDetails VALUES('HR','Denis',1500)
INSERT INTO EmpDetails VALUES('HR','Danny',3000)
INSERT INTO EmpDetails VALUES('IT','David',2000)
INSERT INTO EmpDetails VALUES('IT','John',3000)
示例：
SELECT ed.DeptID
,ed.EmpName
,ed.Salary
FROM (SELECT DeptID, MAX(Salary) MaxSal
FROM EmpDetails
GROUP BY DeptID)AS empmaxsal
INNER JOIN EmpDetails ed
ON empmaxsal.DeptID = ed.DeptID
AND empmaxsal.MaxSal = ed.Salary
不是最优雅，但它有效。
答案 18 :(得分：1)
SELECT DeptID, MAX(Salary)
FROM EmpDetails
GROUP BY DeptID
此查询可以正常运行，但是如果您想要获取与薪水最高的员工相关的其他详细信息，则会发生矛盾。 您可以使用：
SELECT DepatID, a , b, c
FROM EmpDetails
WHERE Salary IN (
SELECT max(Salary)
FROM EmpDetails
GROUP BY DeptID
);
如果您将使用上一个查询，它将仅反映除工资之外的最小值的记录，因为您已使用max函数。
答案 19 :(得分：1)
如果您只想从该表中获得最高薪水，按部门：
SELECT MAX(Salary) FROM TableName GROUP BY DeptID
答案 20 :(得分：1)
select empno
from EMP e
where salary=(select max(sal)
from EMP w
where groupby w.deptno having e.deptno=w.deptno)
我希望它能奏效......
答案 21 :(得分：1)
select deptid, empname, salary from
(Select deptid, empname,salary,
rank() Over(Partition by deptid order by salary desc)as rank from
EmpDetails) emp
where emp.rank = 1
首先按薪酬按降序排列每位员工 等级1，然后只选择deptid，empname，salary。你可以这样做 所有第N组成员。
答案 22 :(得分：1)
使用相关子查询：
<rewrite>
<rules>
<rule name="Imported Rule 1" stopProcessing="true">
<match url="^(.*)/$" ignoreCase="false" />
<conditions>
<add input="{REQUEST_FILENAME}" matchType="IsDirectory" ignoreCase="false" negate="true" />
</conditions>
<action type="Redirect" redirectType="Permanent" url="/{R:1}" />
</rule>
<rule name="Imported Rule 2" stopProcessing="true">
<match url="^" ignoreCase="false" />
<conditions>
<add input="{REQUEST_FILENAME}" matchType="IsDirectory" ignoreCase="false" negate="true" />
<add input="{REQUEST_FILENAME}" matchType="IsFile" ignoreCase="false" negate="true" />
</conditions>
<action type="Rewrite" url="index.php" />
</rule>
</rules>
</rewrite>
答案 23 :(得分：1)
以下查询将显示员工姓名及其各自的部门名称，其中该特定员工姓名的薪水最高。
with T as
(select empname, employee.deptno, salary
from employee
where salary in (select max(salary)
from employee
group by deptno))
select empname, deptname, salary
from T, department
where T.deptno=department.deptno;
我在Oracle数据库上成功执行了上述查询。
答案 24 :(得分：0)
我喜欢2种方法，其中一种方法使用 Rank ，另一种方法使用 ROW_NUMBER
这是我的示例数据
class Block: NSObject {
let block: () -> Void
init(block: @escaping () -> Void) {
self.block = block
}
}
class SomeClass: NSObject {
@objc func foo() {
print("foo...")
let selectorName = "bar:"
let selector = Selector(selectorName)
if self.responds(to: selector) {
let block = Block {
print("block")
}
self.perform(selector, with: block)
}
}
@objc func bar(_ arg1: Block) {
print("bar...")
arg1.block()
}
}
这是我的第一个查询，用于查找最高薪水以及每个性别的具有最高薪水的人
Age Name Gender Salary
----------- -------------------------------------------------- ---------- -----------
1 Mark Male 5000
2 John Male 4500
3 Pavan Male 5000
4 Pam Female 5500
5 Sara Female 4000
6 Aradhya Female 3500
7 Tom Male 5500
8 Mary Female 5000
9 Ben Male 6500
10 Jodi Female 7000
11 Tom Male 5500
12 Ron Male 5000
13 Ramani Female 7000
因此，在这种情况下，我们可以看到这两名女员工“ Jodi”和“ Ramani”之间存在联系。在这种情况下，作为抢七局，我想将年龄作为决定因素，并且应该显示年龄更大的人
with CTE as(
select RANK() over(partition by Gender Order by Salary desc) as [Rank],* from employees)
select * from CTE where [Rank]=1
Rank Age Name Gender Salary
-------------------- ----------- -------------------------------------------------- ---------- -----------
1 10 Jodi Female 7000
1 13 Ramani Female 7000
1 9 Ben Male 6500
通常，在这种情况下，为了找到最高薪水，即使 使用Rank，Dense_Rank或Row_Number（）。但是它们在其他情况下也会产生一些影响。
答案 25 :(得分：0)
with ctesal as (
select DepartmentId , Name , Salary, ROW_Number() OVER (partition by DepartmentId
order by Salary desc) as RowNum
from dbo.Employee
)
select DepartmentId , Name , Salary , RowNum from ctesal where RowNum =2;
这适用于SQL Server。 ROW_Number是SQL Server中的内置函数，它基于partition by和order by子句给出从1开始的计数。最后，我们可以根据我们的要求写条件。
答案 26 :(得分：0)
下面列出的查询将列出每个部门的最高薪水。
export FLASK_DEBUG=1我在Oracle数据库上成功执行了此查询。
答案 27 :(得分：0)
如果您想要部门和最高薪水，请使用
SELECT DeptID, MAX(Salary) FROM EmpDetails GROUP BY DeptID
如果您想在员工和部门中添加更多列，请使用
select Department.Name , emp.Name, emp.Salary from Employee emp
inner join (select DeptID, max(salary) [salary] from employee group by DeptID) b
on emp.DeptID = b.DeptID and b.salary = emp.Salary
inner join Department on emp.DeptID = Department.id
order by Department.Name
如果像这样使用工资（选择最高（工资......）），一个人在另一个部门有相同的工资，那么它就会失败。
答案 28 :(得分：0)
select * from (
select a.* from EmpDetails a
right join (select DeptID,max(salary) as Salary from EmpDetails group by DeptID) b
on b.DeptID=a.DeptID and b.salary=a.salary ) as c group by c.DeptID;
答案 29 :(得分：-1)
从中选择T1。* （选择empname作为e1，department_name，雇员的薪水）作为T1， （按部门名称从员工组中选择max（salary）maxsal，部门名称dept1）作为T2 其中T1.department_name = T2.dept1和T1.salary = maxsal;
答案 30 :(得分：-1)
不确定为什么没有人提到Group By ....有语法。 它专门解决了这些要求。
select EmpName,DeptId,Salary from EmpDetails group by DeptId having Salary=max(Salary);