Question

我试图用Python编写代码，从两个关键字之间的所有单词中打印出来。

    static void Main(string[] args)
    {
        string Parameter = args[0].ToLower().ToString().Replace(Settings.Default.ReplaceText.ToLower(), "");
        string Ext = Settings.Default.PostExtn;
        string url = Settings.Default.UrlPost + "/" + Parameter + "." + Ext;

        WebRequest request = WebRequest.Create(url);
        WebResponse response = request.GetResponse();

        string result;
        using (StreamReader reader = new StreamReader(response.GetResponseStream()))
        {
            result = reader.ReadToEnd();
        }

        RawPrinterHelper.SendValueToPrinter(Settings.Default.PrinterName, Encoding.ASCII.GetBytes(result));

        return;
    }

想要打印出“以打印所有内容”

Answer 1

方法略有不同，让我们创建一个列表，每个元素都是句子中的单词。然后，我们使用list.index()来查找start和end单词在句子中的哪个位置。然后，我们可以在这些索引之间返回列表中的单词。我们希望它以字符串形式而不是列表形式返回，因此我们join将它们与空格一起。

# list of words ['This', 'is', 'a', 'test', ...]
words = scenario.split()

# list of words between start and end ['to', 'print', ..., 'the']
matching_words = words[words.index(start)+1:words.index(end)]

# join back to one string with spaces between
' '.join(matching_words)

结果：

to print out all the

Answer 2

将字符串分割开，然后逐字遍历查找两个关键字所在的索引。一旦有了这两个索引，就可以将这些索引之间的列表合并为一个字符串。

scenario = 'This is a test to see if I can get Python to print out all the words in between Python and words'
start_word = 'Python'
end_word = 'words'

# Split the string into a list
list = scenario.split()

# Find start and end indices
start = list.index(start_word) + 1
end = list.index(end_word)

# Construct a string from elements at list indices between `start` and `end`
str = ' '.join(list[start : end])

# Print the result
print str

Answer 3

最初的问题是您要遍历scenario字符串，而不是将其拆分为单独的单词（使用scenario.split()），但是还有其他问题切换到搜索末尾一旦找到开始，就改为单词，相反，您可能想使用索引来找到两个字符串，然后对该字符串进行切片

scenario = "This is a test to see if I can get Python to print out all the words in between Python and words"
start = "Python"
end = "words"

start_idx = scenario.index(start)
end_idx = scenario.index(end)

print(scenario[start_idx + len(start):end_idx].strip())

Answer 4

您可以使用简单的regex

import re

txt = "This is a test to see if I can get Python to print out all the words in between Python and words"
x = re.search("(?<=Python\s).*?(?=\s+words)", txt)

这是正在使用的正则表达式-> REGEX101

在两个关键字之间打印单词

4 个答案: