Question

我正在做一个作业，该问题绘制了一个正方形的A-J和1-7网格。存在随机生成坐标的函数，例如

[['I5'],                    
['E1', 'F1', 'E2', 'F2'],
['J5', 'J6'],
['G7', 'H7']]

要解决的问题需要一个函数来读取每个列表中的元素，并使用Turtle在其中绘制图块。

如何将字母与每个列表中的数字分开？

仅出于测试目的，我试图打印每个坐标（以便更好地理解，最终结果实际上需要为goto（x，x），然后调用我已经定义的函数画些东西）：

 for instructions in fixed_pattern_16:
        print(instructions[0][1])

哪个输出：

但是，由于每个列表的长度不同，因此当尝试访问位置比最短列表的长度长的元素时，我遇到了超出范围的错误。例如：

print(instructions[2][0])

Answer 1

尝试正则表达式和一些嵌套列表理解：

import re

lists = [['I5'],['E1', 'F1', 'E2', 'F2'],['J5', 'J6'],['G7', 'H7']]

### General format to unpack the list of lists
for i in lists: # Go through each list element
    for x in i: # Go through each element of the element
        print(x) # Print that element to the console

### Flattening that gives us our list comprehension,
### which we can use to unpack this list of lists
[print(x) for i in lists for x in i]

### We want to find a single alphabetic value and capture a single numeric value
### In short, \w looks for a word (letter) and \d looks for a number
### Check out https://regexr.com/ for more info and an interactive canvas.
letter_number_pat = r'\w(\d)'


### We can use re.sub(<pattern>, <replacement>, <string>) to capture and keep our
### numeric value (\1 since it is the first capture group
### Then, we'll anticipate the need to return a list of values, so we'll go with
### the traditional newline (\n) and split our results afterward
number_list = '\n'.join([re.sub(letter_number_pat, r'\1', x) for i in lists for x in i]).split('\n')

输入：number_list

输出：['5', '1', '1', '2', '2', '5', '6', '7', '7']

您可以通过调用set（）函数并将其包装在标准库中的list（）和sorted（）函数中来获得唯一值：

输入：sorted(list(set(number_list)))

输出：['1', '2', '5', '6', '7']

如何将单个字符与列表中的元素分开？

1 个答案: