Question

系统输出两个类型为string的变量； op1如下，

{"fname":"John","mname":"Smith","ID":"2711"}
{"fname":"Nick","mname":"Bart","ID":"3011"}
{"fname":"Nash","mname":"willy","ID":"2811"}
{"fname":"Jack","mname":"Tuna","ID":"2911"}
{"fname":"Peter","mname":"Jill","ID":"2611"}
{"fname":"Aaron","mname":"Sane","ID":"3111"}

和op2如下，

{"fname":"John","mname":"Smith","Age":"Berkley"}
{"fname":"Nash","mname":"willy","Age":"Godson"}
{"fname":"Jack","mname":"Tuna","Age":"Welch"}

我将这些值复制到2个文本文件op1.txt和op2.txt中；我想创建第三个变量（文本文件），该变量仅包含名字和姓氏在op2中存在的ID。请注意，只有2个标记是通用的，即fname和lname。

基于上述输入的输出必须为 [2711，2811，2911]

有没有办法避免将其写入文件并在变量级别本身进行比较？

Answer 1

您应该使用2个列表进行2次循环：

a = [
        {"fname":"John","lname":"Smith","ID":"2711"},
        {"fname":"Nick","lname":"Bart","ID":"3011"},
        {"fname":"Nash","lname":"willy","ID":"2811"},
        {"fname":"Jack","lname":"Tuna","ID":"2911"},
        {"fname":"Peter","lname":"Jill","ID":"2611"},
        {"fname":"Aaron","lname":"Sane","ID":"3111"}
    ]
b = [
    {"fname":"John","lname":"Smith","Age":"Berkley"},
    {"fname":"Nash","lname":"willy","Age":"Godson"},
    {"fname":"Jack","lname":"Tuna","Age":"Welch"},
    {"fname":"FakeJill","lname":"FakeJill","Age":"FakeJill"},
    {"fname":"FakeJack","lname":"FakeJack","Age":"FakeJack"}
     ]
c = []

，然后在此处循环显示字典列表：

for itema in a:
    for itemb in b:
       if itema['fname'] == itemb['fname'] and itema['lname'] == itemb['lname'] :
           c.append(int(itema['ID']))
print(c)

结果将是这样的： [2711，2811，2911]

使用Python从两个文本文件中提取公共行

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