Question

一个两列的数据框，如下所示。

我想给日期指定一个部分，然后将“权重”归一化（使用最小-最大方法）。

这是我的计划：

import pandas as pd


data = {'Date': ["2000-02-01", "2000-03-01", "2000-04-03", "2000-05-01", "2000-06-01", "2000-07-03", "2000-08-01", "2000-09-01", "2000-10-02", "2000-11-01"], 
'Weight' : [478, 26, 144, 9, 453, 24, 383, 314, 291, 286]}

df = pd.DataFrame(data)

df_1 = df.loc[df['Date'] >= "2000-04-01"]

df_1 = (df_1 - df_1.min()) / (df_1.max() - df_1.min())

print df_1

# the ideal output is two columns: 1 for Dates after "2000-04-01". 1 for their correspondent normalized "Weights".

出现错误：

TypeError: unsupported operand type(s) for -: 'str' and 'str'

如何实现？谢谢。

Answer 1

首先将值转换为日期时间，然后仅处理Weight列并覆盖Weight列：

df['Date']  = pd.to_datetime(df['Date'] )
df_1 = df.loc[df['Date'] >= "2000-04-01"]

a = (df_1['Weight'] - df_1['Weight'].min()) / (df_1['Weight'].max() - df_1['Weight'].min())

print (df_1.assign(Weight = a))
        Date    Weight
2 2000-04-03  0.304054
3 2000-05-01  0.000000
4 2000-06-01  1.000000
5 2000-07-03  0.033784
6 2000-08-01  0.842342
7 2000-09-01  0.686937
8 2000-10-02  0.635135
9 2000-11-01  0.623874

Answer 2

日期列的数据类型为字符串。因此您必须将其更改为。为此，您可以使用此方法==>

df['Date']=pd.to_datetime(df['Date'])

熊猫获取部分数据框并标准化值

2 个答案: