Question

我正在使用Python 3.6。我对google和堆栈溢出有一个快速的了解，但是我还没有看到我的问题。问题是我的函数应该找到活动邻居的数量，但返回错误的值（但仅在某些情况下）。

这是代码：

def neighbourCount(i, j):
    neighbours = 0

    try:
        if grid[i-1][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i-1][j] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i-1][j+1] == "1":
            neighbours +=1
    except:
        pass

    try:
        if grid[i][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i][j+1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j-1] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j] == "1":
            neighbours += 1
    except:
        pass

    try:
        if grid[i+1][j+1] == "1":
            neighbours +=1
    except:
        pass

    return(neighbours)



grid = [
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","1","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"]
    ]

newGrid = [
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"],
    ["0","0","0","0","0","0","0","0","0","0"]
    ]


game = 1
while game == 1:

    for i in range(0,10):
        print(*grid[i], sep='  ')

    numNeigh = []

    for i in range(0,10):
        row = []
        for j in range(0,10):
            neighbours = neighbourCount(i, j)
            if grid[i][j] == "1" and ( neighbours>1 and neighbours<4 ):
                newGrid[i][j] = "1"
            if grid[i][j] == "1" and ( neighbours<2 or neighbours>3 ):
                newGrid[i][j] = "0"
            if grid[i][j] == "0" and neighbours == 3:
                newGrid[i][j] = "1"
            row.append(neighbours)

        numNeigh.append(row)

    for i in numNeigh:
        print(i)
    for i in newGrid:
        print(i)

    print("\n\n")

    grid = newGrid

    input()

这是输出（第一块：网格数组）（第二块：每个单元格具有的邻居）（第三块：newGrid数组）：

0  0  0  0  0  0  0  0  0  0 
0  0  0  0  0  0  0  0  0  0
0  1  1  1  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
0  0  0  0  0  0  0  0  0  0
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[1, 2, 3, 3, 2, 0, 0, 0, 0, 0]
[1, 2, 4, 2, 2, 0, 0, 0, 0, 0]
[1, 1, 2, 1, 1, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0]
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '1', '1', '0', '0', '0', '0', '0', '0']
['0', '1', '0', '1', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']
['0', '0', '0', '0', '0', '0', '0', '0', '0', '0']

（以上说明：我也有一个2D数组，用于“ newGrid”，它与“ grid”相同，但只有“ 0”）

中间的块显示每个位置所拥有的邻居数量，但不是在第三行下方显示“ 1、2、1、1、1、0、0 ...”，而是显示“ 1， 2,4,2,2,0,0 ...“

Answer 1

您的问题可能出在创建newGrid的那一行中。除非您正确创建grid的副本（深层副本），否则元素将指向相同的列表（浅层副本）。因此，当您更改newGrid时，grid也将被更改。要正确创建网格副本，请从以下位置更改您的newGrid行：

newGrid = grid.copy()

收件人：

newGrid = [x[:] for x in grid]

注意：使用numpy将在对numpy数组的copy方法的调用上自动创建适当的深层副本。

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1 个答案: