我在python中具有以下功能。
我的目标是生成从1到函数check_overload()返回除0以外的其他值的iperf流量。然后，我计算overload_point_A。毕竟，我转到#Step。 II，其中以相同的过载点值连续发送流量。
#######
# Step. I
#######
count = 10000
r = range(1, count)
for bandwidth in r:
print "============"
print ("bandwidth = "+str(bandwidth))
check = check_overload(SegmentPath, Router_1, Router_2, Router_3, Router_4, step, capacity)
for overload_point_A in check:
if overload_point_A == 0:
print (color.RED + "functionA: iperf " + str(bandwidth)+""+color.END)
break
else:
print "Overload Point I. = ", overload_point_A
del r[bandwidth:]
time.sleep(sleepTime)
break
#######
# Step. II
#######
print("Overloaded of Tunnel 4 at " + str(overload_point_A) + " kbps.")
isrunninga = 0
bandwidth = overload_point_A
while True:
print("Continuous Phase I. bandwidth = "+ str(bandwidth)+" Mbps")
time.sleep(sleepTime)
if isrunninga == 1 :
bandwidth = bandwidth + 1
我面临的问题是，当我修改r = range(1, count)并添加一个整数range（）步长值r = range(1, count, step)时，该函数仅运行Step，有什么方法可以修复它吗？ / p>
这是我不带range()功能的输出：
...
..
======
bandwidth = 7
Link is not overloaded
load = 12.0 < 20 - 2 * 3 = 14
functionA: iperf 7
============
bandwidth = 8
Link is not overloaded
load = 12.0 < 20 - 2 * 3 = 14
functionA: iperf 8
============
bandwidth = 9
Link is overloaded
Overload Point I. = 14.0
Overloaded of Tunnel 4 at 14.0 kbps.
Continuous Phase I. bandwidth = 14.0 Mbps
这是我为range()函数设置step = 3的结果：
...
..
bandwidth = 13
Link is not overloaded
load = 4.0 < 20 - 2 * 3 = 14
functionA: iperf 13
============
bandwidth = 16
Link is not overloaded
load = 11.0 < 20 - 2 * 3 = 14
functionA: iperf 16
============
bandwidth = 19
Link is not overloaded
load = 11.0 < 20 - 2 * 3 = 14
functionA: iperf 19
============
bandwidth = 22
Link is not overloaded
load = 11.0 < 20 - 2 * 3 = 14
functionA: iperf 22
============
bandwidth = 25
Link is overloaded
Overload Point I. = 13.0
============
bandwidth = 28
Link is overloaded
Overload Point I. = 13.0
...