我想使用Ramda通过ID从数组中删除对象。例如:
const arr = [
{id: '1', name: 'Armin'},
{id: '2', name: 'Eren'}, <- delete this object
{id: '3', name: 'Mikasa'}
];
答案 0 :(得分:4)
您可以同时使用filter
或reject
:
R.reject(o => o.id === '2', arr);
R.filter(o => o.id !== '2', arr);
答案 1 :(得分:3)
您可以使用具有组合功能的filter
功能来使用propEq & not
const result = filter(
compose(
not,
propEq('id', 2)
),
array,
)
console.log(result)
答案 2 :(得分:3)
您可以使用reject
。
reject()是filter()的补充。它不包括 谓词返回true的可过滤器。
let res = R.reject(R.propEq('id', '2'))(arr);
答案 3 :(得分:1)
// you could create a generic rejectWhere function
const rejectWhere = (arg, data) => R.reject(R.whereEq(arg), data);
const arr = [
{id: '1', name: 'Armin'},
{id: '2', name: 'Eren'}, // <- delete this object
{id: '3', name: 'Mikasa'}
];
console.log(
'result',
rejectWhere({ id: '2' }, arr),
);
// but also
// rejectWhere({ name: 'Eren' }, arr),
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