我正在尝试为我创建的事件旋转EventHandler上的图像。事件处理程序工作得很好。但是图像不会旋转,我也不知道自己缺少什么。
此UserControl不是这样显示的,而是显示在另一个UserControl的网格中。
<UserControl x:Class="Mabri.Module.P83.View.SchematicSystemView"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
xmlns:local="clr-namespace:Mabri.Module.P83.View"
mc:Ignorable="d"
d:DesignHeight="450" d:DesignWidth="800">
<Image x:Name="drehteller" HorizontalAlignment="Center" VerticalAlignment="Center"/>
</UserControl>
这是XAML的代码,起初我尝试将其放在separat类中,如果可能的话,它甚至会更好,但此刻我正试图使其运行。
{
private System.Windows.Controls.Image drehteller_image;
private int currentAngle = 0;
public SchematicSystemView()
{
EventAggregator.SubscribeEvent(this);
InitializeComponent();
drehteller_image = new System.Windows.Controls.Image()
{
Stretch = Stretch.Uniform,
Source = new BitmapImage(new Uri("pack://application:,,,/Mabri.Module.P83;Component/Images/drehteller_unbestueckt.png")),
RenderTransform = new RotateTransform()
};
drehteller.Source = drehteller_image.Source;
}
public void OnEventHandler(DrehtellerMoved e)
{
EventAggregator.PublishEvent(new LogInfo
{
Title = "Should rotate",
Summary = "The drehteller should rotate now",
Detail = "The drehteller should rotate " + currentAngle + " is the current angle",
LogLevel = LogLevel.Information
});
int steps = e.steps;
double timeforonestep = e.speed / e.steps;
int angle = steps * 72;
int angle_to_reach = currentAngle + angle;
Storyboard storyboard = new Storyboard();
storyboard.Duration = new Duration(TimeSpan.FromSeconds(timeforonestep * steps));
DoubleAnimation rotateAnimation = new DoubleAnimation()
{
From = currentAngle,
To = currentAngle + angle,
Duration = storyboard.Duration
};
Storyboard.SetTarget(rotateAnimation, drehteller);
Storyboard.SetTargetProperty(rotateAnimation, new PropertyPath("(UIElement.RenderTransform).(RotateTransform.Angle)"));
storyboard.Children.Add(rotateAnimation);
storyboard.Begin();
currentAngle = angle_to_reach;
}
}
在测试案例中,e.steps
等于1,e.speed
等于10.0。
我希望图像可以旋转72度,但是由于某些原因,除了处理程序开头的LogMessage之外,什么都没有发生。
答案 0 :(得分:1)
首先,将RotateTransform分配给Image的RenderTransform属性。否则就无法制作动画。
<Image x:Name="drehteller" HorizontalAlignment="Center" VerticalAlignment="Center"
RenderTransformOrigin="0.5,0.5">
<Image.RenderTransform>
<RotateTransform/>
</Image.RenderTransform>
</Image>
然后只设置From
,而不是设置To
和By
。拖放情节提要,然后直接在控件的RenderTransform上启动动画
var animation = new DoubleAnimation
{
By = angle,
Duration = TimeSpan.FromSeconds(...)
};
drehteller.RenderTransform.BeginAnimation(RotateTransform.AngleProperty, animation);
最后,不要创建中间Image元素。那是多余的。
drehteller.Source = new BitmapImage(new Uri("..."));