Question

编译器给出了错误“'void'类型，这里不允许...＆lt; =运算符不能应用于java.lang.String，int ... not a statement”

getHours（）和getSeconds（）返回int类型的实例变量。任何帮助将不胜感激。

 if (userCommand.equals("a")) {
            yourClock.advance();
            System.out.println(yourClock.getSeconds());
            System.out.println("The time is now" +
                    (yourClock.getHours()) <= 9 ? ".0" : ".") +
                    yourClock.getHours() +
                    (yourClock.getMinutes() <= 9 ? ".0" : ".") +
                    yourClock.getMinutes() +
                    (yourClock.getSeconds() <= 9 ? ".0" : ".") +
                    yourClock.getSeconds();

Answer 1

您正在关闭println错误的地方。你在第一次getHours（）调用之后关闭它

if (userCommand.equals("a")) {
            yourClock.advance();
            System.out.println(yourClock.getSeconds());
            System.out.println("The time is now" +
                    (yourClock.getHours() <= 9 ? ".0" : ".") +
                    yourClock.getHours() +
                    (yourClock.getMinutes() <= 9 ? ".0" : ".") +
                    yourClock.getMinutes() +
                    (yourClock.getSeconds() <= 9 ? ".0" : ".") +
                    yourClock.getSeconds());

Answer 2

看起来你太早关闭了打印输出

(yourClock.getHours()) <= 9 ? ".0" : ".") +

之后

结束

getHours())

正在关闭您的打印输出。

Answer 3

让我们看一下这句话：

(yourClock.getHours()) <= 9 ? ".0" : ".")

难道你不认为你缺少'（'这里？

这样更好：

((yourClock.getHours() <= 9) ? ".0" : ".")

Java编译器错误 - 作业分配

3 个答案: