Question

我正在创建自己的报告工具，并且试图弄清楚如何用端口号对IP地址进行排序。

如何对具有端口号的IP地址进行排序，以便先对IP地址进行排序，然后再对端口号进行排序。我可以对IP地址进行排序，但是当与端口号结合使用时，会变得很困难。

a = ['192.168.0.3 (443/tcp)|', '192.168.0.176 (443/tcp)|', '192.168.0.40 (443/tcp)|', '192.168.0.15 (8443/tcp)|', '192.168.0.16 (8443/tcp)|', '192.168.0.12 (443/tcp)|', '192.168.0.9 (3389/tcp)|', '192.168.0.15 (443/tcp)|', '192.168.0.16 (443/tcp)|', '192.168.0.3 (3389/tcp)|', '192.168.0.14 (443/tcp)|']

print(a.sort(key=lambda s: map(int, s.split('.')))) #this works fine with just IP address not with the current format of (xxx/tcp). The pipe is for delimiters so please ignore.

我想先按IP地址对输出进行排序，然后再对每个IP通过端口号进行排序。因此，例如，前几个结果将是：

a= ['192.168.0.3 (443/tcp)|', '192.168.0.3 (3389/tcp)|', 192.168.0.9 (3389/tcp)|, ...']

Answer 1

使用re.findall：

import re

def get_ip_port(x):
    *ips, port = map(int, re.findall('\d+', x))
    return ips, port

sorted(a, key=get_ip_port)

输出：

['192.168.0.3 (443/tcp)|',
 '192.168.0.3 (3389/tcp)|',
 '192.168.0.9 (3389/tcp)|',
 '192.168.0.12 (443/tcp)|',
 '192.168.0.14 (443/tcp)|',
 '192.168.0.15 (443/tcp)|',
 '192.168.0.15 (8443/tcp)|',
 '192.168.0.16 (443/tcp)|',
 '192.168.0.16 (8443/tcp)|',
 '192.168.0.40 (443/tcp)|',
 '192.168.0.176 (443/tcp)|']

说明：

map(int, re.findall('\d+', x))：查找所有数字并将其设为int
*ips, port：解压缩以上int个文件并重新打包成除最后一个（*ips）和最后一个（port）之外的所有文件
sorted(a, key=get_ip_port)：当get_ip_port返回两个键（ips，port）时，sorted首先将a排序为{{1} }，然后根据需要ips。

Answer 2

您可以使用多个条件（以map(int,e[0].split('.'))作为条件1，以int(e[1].lstrip('(').split('/')[0])作为条件2）进行排序，如下所示，

>>> a
['192.168.0.3 (443/tcp)|',
 '192.168.0.176 (443/tcp)|',
 '192.168.0.40 (443/tcp)|',
 '192.168.0.15 (8443/tcp)|',
 '192.168.0.16 (8443/tcp)|',
 '192.168.0.12 (443/tcp)|',
 '192.168.0.9 (3389/tcp)|',
 '192.168.0.15 (443/tcp)|',
 '192.168.0.16 (443/tcp)|',
 '192.168.0.3 (3389/tcp)|',
 '192.168.0.14 (443/tcp)|']
>>> [i.split() for i in a]
[['192.168.0.3', '(443/tcp)|'],
 ['192.168.0.176', '(443/tcp)|'],
 ['192.168.0.40', '(443/tcp)|'],
 ['192.168.0.15', '(8443/tcp)|'],
 ['192.168.0.16', '(8443/tcp)|'],
 ['192.168.0.12', '(443/tcp)|'],
 ['192.168.0.9', '(3389/tcp)|'],
 ['192.168.0.15', '(443/tcp)|'],
 ['192.168.0.16', '(443/tcp)|'],
 ['192.168.0.3', '(3389/tcp)|'],
 ['192.168.0.14', '(443/tcp)|']]

>>> sorted([i.split() for i in a],key=lambda e: (map(int,e[0].split('.')),int(e[1].strip('(').split('/')[0])))
[['192.168.0.3', '(443/tcp)|'],
 ['192.168.0.3', '(3389/tcp)|'],
 ['192.168.0.9', '(3389/tcp)|'],
 ['192.168.0.12', '(443/tcp)|'],
 ['192.168.0.14', '(443/tcp)|'],
 ['192.168.0.15', '(443/tcp)|'],
 ['192.168.0.15', '(8443/tcp)|'],
 ['192.168.0.16', '(443/tcp)|'],
 ['192.168.0.16', '(8443/tcp)|'],
 ['192.168.0.40', '(443/tcp)|'],
 ['192.168.0.176', '(443/tcp)|']]

Answer 3

您可以使用sorted在一行中完成此操作，如下所示：

sorted(a, key=lambda x:x.split(' ')[0])

如何用端口号对IP地址排序？

3 个答案: