Question

我有一个IP地址列表如下

192.168.1.5
69.52.220.44
10.152.16.23
192.168.3.10
192.168.1.4
192.168.2.1

我正在寻找这种方法来对此列表进行排序以匹配以下顺序

10.152.16.23
69.52.220.44
192.168.1.4
192.168.1.5
192.168.2.1

Answer 1

这可能看起来像一个黑客，但它完全符合你的需要：

var unsortedIps =
    new[]
    {
        "192.168.1.4",
        "192.168.1.5",
        "192.168.2.1",
        "10.152.16.23",
        "69.52.220.44"
    };

var sortedIps = unsortedIps
    .Select(Version.Parse)
    .OrderBy(arg => arg)
    .Select(arg => arg.ToString())
    .ToList();

Answer 2

您可以将每个IP地址转换为如此的整数...

69.52.220.44 =>

69 * 255 * 255 * 255 +
52 * 255 * 255 +
220 * 255 +
44

然后按整数表示排序。

Answer 3

您可能会发现此功能也很有用。

public static class ExtensionMethods
{
  public static int CompareTo(this IPAddress x, IPAddress y)
  {
    var result = x.AddressFamily.CompareTo(y.AddressFamily);
    if (result != 0)
      return result;

    var xBytes = x.GetAddressBytes();
    var yBytes = y.GetAddressBytes();

    var octets = Math.Min(xBytes.Length, yBytes.Length);
    for (var i = 0; i < octets; i++)
    {
      var octetResult = xBytes[i].CompareTo(yBytes[i]);
      if (octetResult != 0)
        return octetResult;
    }
    return 0;
  }
}

Answer 4

您可以将Array.Sort函数与我们将创建的用于比较两个IP的函数一起使用：

//ips is string array
Array.Sort(ips, IpCompare);

然后将此函数放入代码中。

private static int IpCompare(string x, string y)
    {
        string ip1 = x + '.', ip2 = y + '.';
        string xSection = "", ySection = "";
        for (int i = 0; i < ip1.Length && i < ip2.Length; i++)
        {
            if (ip1[i] == '.' && ip2[i] == '.')
            {
                if (xSection != ySection)
                    return int.Parse(xSection) - int.Parse(ySection);
                xSection = ""; // Start compare the next section
                ySection = "";
            }
            else if (ip1[i] == '.') return -1; //The first section is smaller because it's length is smaller
            else if (ip2[i] == '.') return 1;
            else
            {
                xSection += ip1[i];
                ySection += ip2[i];
            }
        }
        return 0; 
        //If we would find any difference between any section it would already return something.
        //so that mean that both IPs are the same
   }

Answer 5

简单的解决方案不需要黑客。只需对地址段进行Split（），用零填充这些段，然后将它们重新连接在一起。将这一行静态方法放入这样的静态类中：

public static class StringHelper
{
    public static string IpAddressLabel(string ipAddress)
        => string.Join(".", ipAddress.Split('.').Select(part => part.PadLeft(3, '0')));
}

然后随意调用：

 => new[] {"192.168.1.100", "192.168.1.1", "192.168.1.19"}
      .OrderBy(ip => StringHelper.IpAddressLabel(ip));

此外，当需要可排序的标签时，它可以用作文件名或其他位置：

192.168.001.001.log
192.168.001.019.log
192.168.001.100.log

如何使用c＃对Ip地址列表进行排序

5 个答案: