我有一个看起来像这样的数据集:
Key TypeSeq Type Duration
-------------------------------------
29671461 10 1001 4
29671461 20 1002 2
29671461 30 1003 0
29671461 40 1004 0
29671461 70 1007 261
29671463 10 1001 3
29671463 20 1002 5
29671463 30 1003 7
29671463 40 1004 8
29671463 70 1007 261
我找到了这个,但是我想按ID而不是按其分组
select t1.id, t1.SomeNumt, SUM(t2.SomeNumt) as sum
from @t t1
inner join @t t2 on t1.id >= t2.id
group by t1.id, t1.SomeNumt
order by t1.id
我需要第5列,该列按关键列进行累加总计
答案 0 :(得分:0)
您可以将sum()
用作窗口功能。如果将order by
与select "Key", TypeSeq, type, duration,
sum(duration) over (partition by "Key" order by TypeSeq) as sum
from the_table
order by "Key", TypeSeq;
一起使用,您将获得一个累积的总和:
IEntityTypeConfiguration