Question

在以下示例中，我每天获取总计。我需要获取与DPetAcNo相关的累计总数。

    SELECT
DPetAcNo as AcNo,
SUM(DPetAmount) as PetTotal
FROM PettyDetail
WHERE DPetComCode='15'
and DPetLocCode='01'
and DPetDate=CONVERT(date,'20181113',111)
group by
DPetAcNo

Answer 1

解决此问题的规范方法是：

SELECT DPetAcNo as AcNo, SUM(DPetAmount) as PetTotal,
       SUM(SUM(DPetAmount)) OVER (ORDER BY DPetAcNo) as Running_PetTotal
FROM PettyDetail
WHERE DPetComCode = '15' AND
      DPetLocCode = '01' AND
      DPetDate = '20181113'
GROUP BY DPetAcNo;

如果这不能满足您的要求，那么您需要清楚什么不起作用以及您实际想要的结果集。

如何获得累计总数

1 个答案: