Question

试图解决在尝试向视图显示一些数据时遇到的错误。我正在使用v5.7，我感觉它可能与控制器中的index方法有关，这可能是非常错误的。如果需要更多信息，请告诉我。

试图获取非对象（0）的属性'slug'

路线：

Route::get('/category/{category}','BlogController@category')->name('category');

BlogCategory模型

namespace App;

use Illuminate\Database\Eloquent\Model;

class BlogCategory extends Model
{
   protected $fillable = ['title', 'slug']; 

   public function posts()
   { 
     return $this->hasMany(Post::class); 
   }

   public function getRouteKeyName()
   { 
     return 'slug'; 
   }
}

发布模型

public function category()
{
    return $this->belongsTo(BlogCategory::class);
}

控制器：

protected $limit = 3;

public function index()
{
    $categories = BlogCategory::with(['posts' => function ($query) {
        $query->published();
    }])->orderBy('title', 'asc')->get();

    $posts = Post::with('author')
        ->latestFirst()
        ->published()
        // ->filter(request()->only(['term','year','month']))
        ->simplePaginate($this->limit);

    return view('pages.frontend.blog.index', compact('posts', 'categories'));
}

public function category(BlogCategory $category)
{
    $categoryName = $category->title;

    $categories = BlogCategory::with(['posts' => function ($query) {
        $query->published();
    }])->orderBy('title', 'asc')->get();

    $posts = $category->posts()
        ->with('author')
        ->latestFirst()
        ->published()
        ->simplePaginate($this->limit);

    return view("pages.frontend.blog.index", compact('posts', 'categories', 'categoryName'));
}

查看：

@foreach ($posts as $post)
    <article class="post-item">
        @if ($post->image_url)
            <div class="post-item-image">
                <a href="{{ route('blog.show', $post->slug) }}">
                    <img src="{{ $post->image_url }}" alt="">
                </a>
            </div>
        @endif
        <div class="post-item-body">
            <div class="padding-10">
                <h2>
                    <a href="{{ route('blog.show', $post->slug) }}">{{ $post->title }}</a>
                </h2>
                {!! $post->excerpt_html !!}
            </div>

            <div class="post-meta padding-10 clearfix">
                <div class="pull-left">
                    <ul class="post-meta-group">
                        <li>
                            <i class="fa fa-user"></i>
                            <a href="#"> {{ $post->author->name }} </a>
                        </li>
                        <li>
                            <i class="fa fa-clock-o"></i>
                            <time> {{ $post->date }}</time>
                        </li>
                        <li>
                            <i class="fa fa-folder"></i>
                            <a href="{{ route('category', $post->category->slug) }}"> {{ $post->category->title }}</a>
                        </li>
                        <li>
                            <i class="fa fa-comments"></i>
                            <a href="#">4 Comments</a>
                        </li>
                    </ul>
                </div>
                <div class="pull-right">
                    <a href="{{ route('blog.show', $post->slug) }}">Continue Reading &raquo;</a>
                </div>
            </div>
        </div>
    </article>
@endforeach

发布表

博客猫表

Answer 1

belongsTo函数在posts表中接受第二个参数作为外键的名称，如果不提供该参数，框架将尝试猜测给定外键名称的外键列名称是什么。在您的情况下，category()充当模式，因此框架正在搜索category_id，但是，您的外键列名称为blog_category_id。

public function category()
{
    return $this->belongsTo(BlogCategory::class, 'blog_category_id');
}

Answer 2

如果此视图与索引方法相关，则应在控制器的索引中调用类别关系！

public function index()
{
    $categories = BlogCategory::with(['posts' => function ($query) {
        $query->published();
    }])->orderBy('title', 'asc')->get();

    $posts = Post::with('author')
        ->category()
        ->latestFirst()
        ->published()
        // ->filter(request()->only(['term','year','month']))
        ->simplePaginate($this->limit);

    return view('pages.frontend.blog.index', compact('posts', 'categories'));
}

试图获取非对象5.7的属性“子弹”

2 个答案: