试图获得非对象Laravel 5.5的属性'slug'

Question

我的AdminMiddleware代码是::

#include <iostream>
using namespace std;

char askQuestion(int questionNumber, char* question, char* optionA, char* optionB, char* optionC) {
char answer{};
cout << questionNumber << ".)" << question << "\n";
cout << optionA << "\n";
cout << optionB << "\n";
cout << optionC << "\n";
cin >> answer;
return answer;
}
int main()
{
char answer1;
char answer2;
char questionNumber;

questionNumber = 1;
answer1 = askQuestion(questionNumber, "Who is the Big Red Dog?", "A.)Milo", "B.)Clifford", "C.)Jack");

(answer1 == 'B') ? cout << "CORRECT!!!" : cout << "INCORRECT!!!";
cout << endl;

return 0;
}

当我想去::

<?php

namespace App\Http\Middleware;

use Closure;
use Sentinel;

class AdminMiddleware
{
    /**
     * Handle an incoming request.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Closure  $next
     * @return mixed
     */
    public function handle($request, Closure $next)
    {
        if(Sentinel::check()&&Sentinel::getUser()->roles()->first()->slug =='admin')
            return $next($request);
        else
            return redirect('/accessories');    
    }
}

它显示如下错误：

  

试图获取非对象的属性'slug'

Answer 1

这可能是因为 Sentinel::getUser()->roles() 不是一个对象，意味着：用户没有任何角色

添加另一张支票

if(Sentinel::check() && isset(Sentinel::getUser()->roles) && Sentinel::getUser()->roles()->first()->slug =='admin'){
//Other code

}