Question

大家好，

我已经在站点上找到了解决类似问题的解决方案，它只有一列，这对我有所帮助。但是，当我需要对数组进行嵌套时，我会停留在最后一部分。

这是到目前为止的查询：

#StandardSQL
With Data AS
(
SELECT 'aaa' as Item, 'EA/BX/PA' as UOM, '1/10/100' as Factor UNION ALL
SELECT 'bbb' as Item, 'EA/PA' as UOM, '1/50' as Factor UNION ALL
SELECT 'ccc' as Item, null as UOM, null as Factor 
),
SplitData AS
(
SELECT
Item,
SPLIT(UOM, "/") as UOM,
SPLIT(Factor, "/") as Factor
FROM Data
)
SELECT
*
FROM
SplitData,
UNNEST(SplitData.UOM),UNNEST(SplitData.Factor)

结果是：

--Row---+--Item---+--UOM--¦--Factor--+--f0_--+--f1_--
   1    ¦  aaa    ¦  EA   ¦    1     ¦  EA   ¦  1
        ¦         ¦  BX   ¦   10     ¦       ¦
        ¦         ¦  PA   ¦  100     ¦       ¦
--------+---------+-------+----------+-------+-------    
   2    ¦  aaa    ¦  EA   ¦    1     ¦  EA   ¦  10
        ¦         ¦  BX   ¦   10     ¦       ¦
        ¦         ¦  PA   ¦  100     ¦       ¦
--------+---------+-------+----------+-------+-------

等，等等

我想看的是这个

--Row---+--Item---+--UOM--¦--Factor--+
   1    ¦  aaa    ¦  EA   ¦    1     ¦
--------+---------+-------+----------+
   2    ¦  aaa    ¦  BX   ¦   10     ¦
--------+---------+-------+----------+
   3    ¦  aaa    ¦  PA   ¦  100     ¦
--------+---------+-------+----------+
   4    ¦  bbb    ¦  EA   ¦    1     ¦ 
--------+---------+-------+----------+

等，等等

我发现问题是我的查询中出现双重错误，试图将每个查询都连接在一起，但是当我仅选择ItemCode时，根本没有得到UOM和因子...

请问我需要如何修改查询才能获得此结果？

Answer 1

尝试一下：

With

Data AS (
    SELECT 'aaa' as Item, 'EA/BX/PA' as UOM, '1/10/100' as Factor UNION ALL
    SELECT 'bbb' as Item, 'EA/PA' as UOM, '1/50' as Factor UNION ALL
    SELECT 'ccc' as Item, null as UOM, null as Factor 
),

SplitData AS (
    SELECT
        Item,
        SPLIT(UOM, "/") as UOM,
        SPLIT(Factor, "/") as Factor
    FROM
        Data
)

SELECT
    *,
    Factor[offset(uom_offset)] as unnested_factor
FROM
    SplitData as sd
    cross join UNNEST(sd.UOM) as unnested_uom  -- use left join if you want to display 'ccc' Item
        with offset as uom_offset

一个：

With

Data AS (
    SELECT 'aaa' as Item, 'EA/BX/PA' as UOM, '1/10/100' as Factor UNION ALL
    SELECT 'bbb' as Item, 'EA/PA' as UOM, '1/50' as Factor UNION ALL
    SELECT 'ccc' as Item, null as UOM, null as Factor
),

SplitData AS (
    SELECT
        Item,
        SPLIT(UOM, "/") as UOM,
        SPLIT(Factor, "/") as Factor
    FROM Data
)

SELECT
    sd.*,
    unnested_uom,
    unnested_factor
FROM
    SplitData as sd
    left join UNNEST(sd.UOM) as unnested_uom
        with offset as uom_offset
    left join UNNEST(sd.Factor) as unnested_factor
        with offset as factor_offset
where
    coalesce(uom_offset, factor_offset, 1)
    = coalesce(factor_offset, uom_offset, 1)

Answer 2

以下是用于BigQuery Standard SQL的数据，并假设（基于示例数据的示例）UOM和Factor中的元素数相同

#standardSQL
SELECT item, u AS UOM, f AS Factor
FROM `project.dataset.data`
LEFT JOIN UNNEST(SPLIT(UOM, '/')) u WITH OFFSET
JOIN UNNEST(SPLIT(Factor, '/')) f WITH OFFSET
USING(OFFSET)

如果要应用于您的问题的样本数据-结果为

Row item    UOM     Factor   
1   aaa     EA      1    
2   aaa     BX      10   
3   aaa     PA      100  
4   bbb     EA      1    
5   bbb     PA      50

尝试将多列中的单元格拆分为行-UNNEST查询

2 个答案: