Question

我必须选择属于user_id 1和2的business_type_id。

例如：以下是我的桌子：

user_id     business_type_id
101             1
101             1       
101             1
101             2
101             2
102             1
102             1
103             2       
103             2
103             2

预期输出：

我想在两个user_id business_type_id中都找到1 & 2。

结果：

101->是两个business_type_id中都存在的user_id。

Answer 1

您可以进行聚合：

select user_id
from table t
where business_type_id in (1, 2)
group by user_id
having count(distinct business_type_id) = 2;

Answer 2

SELECT user_id FROM table_name WHERE business_type_id IN (1, 2) GROUP BY user_id。

Answer 3

如果要使user_id与business_type_id = 1或business_type_id = 2

select distinct  user_id 
from  my_table  
where business_type_id in (1,2 )

如果您希望user_id的business_type_id = 1 AND business_type_id = 2

select  user_id 
from  my_table  
where business_type_id in (1,2 )
group by user_id  
having count(distinct business_type_id ) = 2

并且如果只希望user_id在business_type_id = 1 AND business_type_id NOT = 2的情况下

select  user_id 
from  my_table  
where user_id  not  in  (
  select distinct user_id 
  from  my_table  
  where business_type_id = 2
) 
and  business_type_id  = 1

查询以选择同一列上具有不同值的条件

3 个答案: