如果你很善良,我需要一些以下代码的帮助。 基本上我有一个树节点,可以记住它的父节点,深度级别和他当前的状态(2D数组)。 大多数变量名都是用我的母语编写的,我希望这不是问题:
public class Nod implements Cloneable {
private Nod parinte;//parent node
private int[][] stare;//state
private int cost;//depth-level
private String actiune;//the action used to obtain this node
private volatile int hashCode = 0;
public boolean equals(Object obj)
{
if(this == obj)
{
return true;
}
if (!(obj instanceof Nod))
{
return false;
}
Nod nod = (Nod)obj;
return cost == nod.getCost() && actiune.equals(nod.getActiune())
&& stare.equals(nod.getStareNod());
}
public int hashCode()
{
StringBuffer strBuff = new StringBuffer();
try
{
int n = Problema.Dimensiune();//returns the dimension of state matrix
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
strBuff.append(stare[i][j]);
strBuff.append(cost);
strBuff.append(actiune);
String str = strBuff.toString();
hashCode = str.hashCode();
}
catch (IOException e) {
e.printStackTrace();
}
return hashCode;
}
public Object clone() throws CloneNotSupportedException
{
return super.clone();
}
public static boolean goUp(int[][] st) throws IOException
{
int n = Problema.Dimensiune();
boolean ok = false;
int[][] a = st;
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
{
if (a[i][j] == 0)
if (i != 0)
ok = true;
}
return ok;
}
public static boolean goDown(int[][] st) throws IOException
{
int n = Problema.Dimensiune();
boolean ok = false;
int[][] a = st;
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
{
if (a[i][j] == 0)
if (i != (n-1))
ok = true;
}
return ok;
}
public static boolean goLeft(int[][] st) throws IOException
{
int n = Problema.Dimensiune();
boolean ok = false;
int[][] a = st;
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
{
if (a[i][j] == 0)
if (j != 0)
ok = true;
}
return ok;
}
public static boolean goRight(int[][] st) throws IOException
{
int n = Problema.Dimensiune();
boolean ok = false;
int[][] a = st;
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
{
if (a[i][j] == 0)
if (j != (n-1))
ok = true;
}
return ok;
}
public static int[] Zero(int[][] st) throws IOException
{
int[][] a = st;
int n = Problema.Dimensiune();
int[] b = new int[2];
for (int i=0;i<n;i++)
for (int j=0;j<n;j++)
if (a[i][j] == 0)
{
b[0] = i;
b[1] = j;
}
return b;
}
public static int[][] Actiune(int[][] st, String s) throws IOException
{
int[][] a = st;
int[] b = Zero(st);
if ((goRight(st) == true) && (s == "right"))
{
a[b[0]][b[1]] = a[b[0]][b[1]+1];
a[b[0]][b[1]+1] = 0;
}
if ((goLeft(st) == true) && (s == "left"))
{
a[b[0]][b[1]] = a[b[0]][b[1]-1];
a[b[0]][b[1]-1] = 0;
}
if ((goUp(st) == true) && (s == "up"))
{
a[b[0]][b[1]] = a[b[0]-1][b[1]];
a[b[0]-1][b[1]] = 0;
}
if ((goDown(st) == true) && (s == "down"))
{
a[b[0]][b[1]] = a[b[0]+1][b[1]];
a[b[0]+1][b[1]] = 0;
}
return a;
}
public Nod(){}
public Nod (int[][] st)
{
parinte = null;
stare = st;
cost = 0;
actiune = null;
}
public Nod (Nod nod)
{
parinte = nod.parinte;
stare = nod.stare;
cost = nod.cost;
actiune = nod.actiune;
}
public Nod(Nod nodp, String ac) throws IOException
{
this.parinte = nodp;
this.cost = parinte.getCost()+1;
this.actiune = ac;
this.stare = Actiune(parinte.getStareNod(),actiune);
}
public void setCost(int cost)
{
this.cost = cost;
}
public int getCost(){
return this.cost;
}
public void setStareNod(int[][] stare)
{
this.stare = stare;
}
public int[][] getStareNod(){
return this.stare;
}
public void setNodParinte(Nod parinte)
{
this.parinte = parinte;
}
public Nod getNodParinte() throws IOException{
return this.parinte;
}
public void setActiune(String actiune)
{
this.actiune = actiune;
}
public String getActiune()
{
return this.actiune;
}
}
现在,我创建一个初始节点,然后创建一个子节点。问题是当我创建子节点时,父节点的2D数组变得与子节点相同。我试图克隆节点对象但它没有修复它。如果有人有一个想法如何解决它并分享它,我将不胜感激。
public class test {
public static void main(String[] args) throws IOException, CloneNotSupportedException
{
int[][] p = Problema.stareInitiala();
Nod nod = new Nod(p);
Nod nodc = (Nod) nod.clone();
Nod nod1 = new Nod(nodc,"right");
Nod nod1c = (Nod) nod1.clone();
Nod nod2 = new Nod(nod1c,"up");
if (nod.getStareNod().equals(nod.getStareNod()))
System.out.print("ok");
else
System.out.print("not ok");
}
}
所以如果p = {{7,2,4},{5,0,6},{8,3,1}} if语句应该返回“not ok”,而是我得到“ok”消息。
答案 0 :(得分:3)
克隆机制没有任何破坏或错误。只是一群或不了解它的程序员,这里有一个适合你的课程。
public Object clone() {
try {
Nod clone = (Nod)super.clone();
clone.stare = (int[][])stare.clone();
return clone;
} catch (CloneNotSupportedException cnse) {
//won't happen;
throw new RuntimeError("Won't happen");
}
}
此实现假定克隆要使用与原始父级相同的父级。如果不是这种情况,您还需要克隆它,或者将父项设置为null。
答案 1 :(得分:0)
您可能希望查看Object的clone()方法的documentation。默认克隆实现(即,如果您实现了Cloneable,则执行)执行浅拷贝。这可能不是你想要的,你可以通过编写自己的复制方法来获得更好的效果。