我有一个如下所示的data.frame
sss = structure(list(a = structure(c(16266, 16267, 16268, 16269, 16271,
16272, 16273, 16274, 16275, 16276), class = "Date"), b = c("xxx",
"xxx", "xxx", "xxx", "xxx", "xxx", "xxx", "xxx", "c", "xxx"),
c = c(1.35668, 1.352385, 1.35258, 1.35245, 1.352415, 1.35214,
1.346835, 1.346215, 1.34635, 1.343145)), row.names = c(NA,
-10L), class = "data.frame")
现在我想使用如下的reshape包来抛弃此data.frame
reshape2::dcast(sss, formula = a ~ b, fun.aggregate = mean, fill = NA, value.var = "c")
但是,我的错误却越来越少了- *
Error in vapply(indices, fun, .default) : values must be type 'logical',
but FUN(X[[9]]) result is type 'double'
*
任何指针为什么会出现错误,都会有所帮助。
> sessionInfo()
R version 3.6.1 (2019-07-05)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 18.04.2 LTS
Matrix products: default
BLAS: /usr/lib/x86_64-linux-gnu/blas/libblas.so.3.7.1
LAPACK: /usr/lib/x86_64-linux-gnu/lapack/liblapack.so.3.7.1
locale:
[1] LC_CTYPE=C.UTF-8 LC_NUMERIC=C LC_TIME=C.UTF-8
[4] LC_COLLATE=C.UTF-8 LC_MONETARY=C.UTF-8 LC_MESSAGES=C.UTF-8
[7] LC_PAPER=C.UTF-8 LC_NAME=C LC_ADDRESS=C
[10] LC_TELEPHONE=C LC_MEASUREMENT=C.UTF-8 LC_IDENTIFICATION=C
attached base packages:
[1] stats graphics grDevices utils datasets methods base
loaded via a namespace (and not attached):
[1] compiler_3.6.1 magrittr_1.5 plyr_1.8.4 tools_3.6.1 reshape2_1.4.3
[6] Rcpp_1.0.1 stringi_1.4.3 stringr_1.4.0
答案 0 :(得分:2)
与NA
是逻辑而不是数字有关;更改为NA_real_
以解决错误:
reshape2::dcast(sss, formula = a ~ b, fun.aggregate = mean, fill = NA_real_, value.var = "c")
a c xxx
1 2014-07-15 NA 1.356680
2 2014-07-16 NA 1.352385
3 2014-07-17 NA 1.352580
4 2014-07-18 NA 1.352450
5 2014-07-20 NA 1.352415
6 2014-07-21 NA 1.352140
7 2014-07-22 NA 1.346835
8 2014-07-23 NA 1.346215
9 2014-07-24 1.34635 NA
10 2014-07-25 NA 1.343145
答案 1 :(得分:0)
data.table
library(data.table)
dcast.data.table(setDT(sss), a~ b, fun.aggregate = mean, fill = NA, value.var = 'c')
a c xxx
1: 2014-07-15 NA 1.356680
2: 2014-07-16 NA 1.352385
3: 2014-07-17 NA 1.352580
4: 2014-07-18 NA 1.352450
5: 2014-07-20 NA 1.352415
6: 2014-07-21 NA 1.352140
7: 2014-07-22 NA 1.346835
8: 2014-07-23 NA 1.346215
9: 2014-07-24 1.34635 NA
10: 2014-07-25 NA 1.343145
我认为问题可能在于您在b
列中有“ c”作为值,而在名称列中有“ c”作为我们的value.var