是否可以使用qmlRegisterType函数将init参数传递给注册到QML的python类?如果是这样,当在QML中实例化该类时会通过它们吗?
我已经用qmlRegisterType注册了该类,但是没有看到将另一个类实例作为对象传递的方法。我确实看到了一种注册扩展对象的方法,但是根据文档,这些对象只能是属性。我想传入另一个实例化的类,以便可以在我向QML注册的类中访问其方法和属性。
如何在Python中实例化该类:
from PySide2.QtWidgets import QApplication
from PySide2.QtQml import QQmlApplicationEngine, qmlRegisterType, QQmlComponent
from PySide2.QtCore import QObject
from app import Sites
from models import RoutesConn
def main():
# create the application instance
app = QApplication(sys.argv)
# create a QML engine
engine = QQmlApplicationEngine()
# instantiate Sites instance
sites = Sites()
# instantiate RoutesConn instance, and pass in sites instance
routesconn = RoutesConn(sites)
# this could be provided to qml as an object
engine.rootContext().setContextProperty('RoutesConn', routesconn)
但是,如果在qml中注册为类,则无法传递sites实例。我认为,当在QML中实例化网站类时,也可以将其注册到qml并传递给RoutesConn,但是我还没有找到一种方法。
在Python中将类注册到QML:
qmlRegisterType(RoutesConn, 'RoutesConn', 1, 0, 'RoutesConn')
QML:
import RoutesConn 1.0
RoutesConn {
id: rconn
....
}
我希望有一种方法可以在向qml注册后的初始化过程中将对象传递到类中,但事实并非如此。
答案 0 :(得分:0)
TL; DR; 不,不可能。
QML希望通过qmlRegisterType注册的QObject仅具有一个将QObject作为父对象接收的构造函数(qmlRegisterType不会构建该对象,仅使其在QML中可用):
class Foo(QtCore.QObject):
def __init__(self, parent=None):
super().__init__(parent)
# ...
如果要传递其他对象,则必须通过Slot或Property:
from PySide2 import QtCore, QtGui, QtQml
class Bar(QtCore.QObject):
def test(self):
print("test")
class Foo(QtCore.QObject):
def __init__(self, parent=None):
super().__init__(parent)
self.m_bar = None
@QtCore.Slot(Bar)
def load_bar(self, bar):
self.m_bar = bar
@QtCore.Slot()
def test_bar(self):
if self.m_bar is not None:
self.m_bar.test()
if __name__ == "__main__":
import os
import sys
app = QtGui.QGuiApplication(sys.argv)
QtQml.qmlRegisterType(Foo, 'TestComponents', 1, 0, 'Foo')
QtQml.qmlRegisterType(Bar, 'TestComponents', 1, 0, 'Bar')
engine = QtQml.QQmlApplicationEngine()
file = os.path.join(os.path.dirname(os.path.realpath(__file__)), "main.qml")
engine.load(file)
if not engine.rootObjects():
sys.exit(-2)
sys.exit(app.exec_())
import QtQuick 2.5
import QtQuick.Controls 1.4
import QtQuick.Controls 2.5
import TestComponents 1.0
ApplicationWindow {
visible: true
width: 640
height: 480
color: "whitesmoke"
Foo{
id: foo
Component.onCompleted: load_bar(bar)
}
Bar{
id: bar
}
Button {
text: "Cancel"
onClicked: foo.test_bar()
anchors.centerIn: parent
}
}
from PySide2 import QtCore, QtGui, QtQml
class Bar(QtCore.QObject):
def test(self):
print("test")
class Foo(QtCore.QObject):
barChanged = QtCore.Signal()
def __init__(self, parent=None):
super().__init__(parent)
self.m_bar = None
def getBar(self):
return self.m_bar
def setBar(self, bar):
if self.m_bar != bar:
self.m_bar = bar
self.barChanged.emit()
bar = QtCore.Property(Bar, fget=getBar, fset=setBar, notify=barChanged)
@QtCore.Slot()
def test_bar(self):
if self.m_bar is not None:
self.m_bar.test()
if __name__ == "__main__":
import os
import sys
app = QtGui.QGuiApplication(sys.argv)
QtQml.qmlRegisterType(Foo, "TestComponents", 1, 0, "Foo")
QtQml.qmlRegisterType(Bar, "TestComponents", 1, 0, "Bar")
engine = QtQml.QQmlApplicationEngine()
file = os.path.join(os.path.dirname(os.path.realpath(__file__)), "main.qml")
engine.load(file)
if not engine.rootObjects():
sys.exit(-2)
sys.exit(app.exec_())
import QtQuick 2.5
import QtQuick.Controls 1.4
import QtQuick.Controls 2.5
import TestComponents 1.0
ApplicationWindow {
visible: true
width: 640
height: 480
color: "whitesmoke"
Foo{
id: foo
bar: bar_object
}
Bar{
id: bar_object
}
Button {
text: "Cancel"
onClicked: foo.test_bar()
anchors.centerIn: parent
}
}