Oracle中某些列中的行之间值相等的总和

Question

查询如下：

SELECT TBL.ID, TBL.CODE1, TBL.CODE2, TBL.CODE3, TBL.CODE4, TBL.QTY
FROM DB.TBL TBL
GROUP BY TBL.ID, TBL.CODE1, TBL.CODE2, TBL.CODE3, TBL.CODE4, TBL.QTY

这将返回如下数据：

    ID  |   CODE1   |   CODE2   |   CODE3   |   CODE4   |   QTY
--------+-----------+-----------+-----------+-----------+----------
    1   |   H1      |   G2      |   R3      |   MM      |   5
    2   |   F1      |   E2      |   J3      |   SS      |   2
    3   |   H1      |   G2      |   R3      |   LL      |   8
    4   |   C1      |   I2      |   O3      |   PP      |   6
    5   |   F1      |   E2      |   J3      |   EE      |   1

如何在行之间的QTY，CODE1和CODE2列相同的情况下添加列CODE3的总和？

    ID  |   ... |   QTY |   SUM
--------+-------+-------+----------
    1   |   ... |   5   |   13
    2   |   ... |   2   |   3
    3   |   ... |   8   |   13
    4   |   ... |   6   |   6
    5   |   ... |   1   |   3

类似以下内容：

SUM(CASE WHEN TBL.CODE1=TBL.CODE1 AND TBL.CODE2=TBL.CODE2 AND TBL.CODE3=TBL.CODE3 THEN TBL.QTY ELSE 0 END)

Answer 1

您可以使用窗口功能：

public void UsageExample()
  {

    Console.WriteLine(SHA.GenerateSHA512String("abc"));
    //returns DDAF35A193617ABACC417349AE20413112E6FA4E89A97EA20A9EEEE64B55D39A2192992A274FC1A836BA3C23A3FEEBBD454D4423643CE80E2A9AC94FA54CA49F
  }