Sum 2列，其中值相同

Question

我将从表开始： 查询：

SELECT taw.user_id AS taw_user_id, COALESCE(SUM(tai.bid), 0) AS tai_bid, taw.win AS taw_win
FROM tb_auction_winners taw JOIN
     tb_aukciono_istorija tai
     ON taw.id = tai.aukciono_id
WHERE tai.user_id = 206 AND taw.user_id = 206
GROUP BY aukciono_id, taw.user_id;

我的问题是我无法获得我想要的结果（使用inspect元素更改）：

它应该对tai_bid相同的所有taw_win和taw_user_id值求和。我已阅读SQL query to sum the data和How to take sum of column with same id in SQL?个帖子，但它没有帮助。使用GROUP BY aukciono_id, taw_user_id一切都应该没问题，但它不起作用。我想这是一个非常简单的修复，但我找不到有什么问题:(请帮帮我。

SQL FIDDLE：http://sqlfiddle.com/#!9/6945a/1

Answer 1

如果我做对了：你只想用taw_user_id求和 - 这就是GROUP BY子句中的唯一一列

  SELECT taw.user_id AS taw_user_id
      ,SUM(taw.win) AS taw_win
      ,SUM(tai.bid) AS tai_bid
  FROM tb_auction_winners taw
  INNER JOIN  
  ( SELECT aukciono_id, user_id, SUM(bid) as bid
      FROM tb_aukciono_istorija
      group by aukciono_id, user_id
   )  tai
  ON taw.id = tai.aukciono_id
  AND taw.user_id  = tai.user_id
 WHERE taw.user_id = 206 
 GROUP BY taw.user_id

Answer 2

检查此查询

   select taw_user_id,sum(taw_win) as taw_win,sum(tai_bid) as tai_bid from
    (
    select taw.user_id AS taw_user_id,sum(win) as taw_win ,(select sum(bid) from tb_aukciono_istorija
    where user_id=taw.user_id and taw.id =aukciono_id ) AS tai_bid from tb_auction_winners   taw where user_id=206
    group by  taw.id)   temp

http://sqlfiddle.com/#!9/6945a/86