Question

所以我有一个包含多个对象的对象数组，我想从对象中删除日期键，即createdDate和modifiedDate

我尝试过使用for循环并使用delete函数，但是什么也没发生。

 var data = matchScoreData.tbl_FallOfWicket;
 matchScoreData.tbl_FallOfWicket.forEach(element => {
    if (matchScoreData.tbl_FallOfWicket.hasOwnProperty("createdDate")) {
                  delete ["createdDate"];
    }
 });
 console.table(data);

 var matchScoreData = {
    "tbl_FallOfWicket": [
                {
                  "pk_fallWicketID": 119,
                  "fk_matchID": 133137,
                  "fk_teamID": 141065,
                  "fk_dismissTypeID": 3,
                  "fk_dismissPlayerID": 969155,
                  "run": 40,
                  "wicket": 1,
                  "over": "5.1",
                  "inning": 1,
                  "createdDate": "2018-08-18T03:06:12+0000",
                  "modifiedDate": "",
                },
                {
                  "pk_fallWicketID": 120,
                  "fk_matchID": 133137,
                  "fk_teamID": 141065,
                  "fk_dismissTypeID": 1,
                  "fk_dismissPlayerID": 939721,
                  "run": 88,
                  "wicket": 2,
                  "over": "9.5",
                  "createdDate": "2018-08-18T03:06:12+0000",
                  "modifiedDate": "",
                  "inning": 1
       }
    ]};

我在输出中得到相同的值

Answer 1

您的问题是您正在使用window.rootViewController = HostingController(rootView: ContentView())，它应该是delete["createdDate"]，以便它可以从迭代的delete element["createdDate"]中删除正确的属性。

element

注意：

您的代码还有一个更大的问题

matchScoreData.tbl_FallOfWicket.forEach(element => {
  if (element.hasOwnProperty("createdDate")) {
    delete element["createdDate"];
  }
});

if (matchScoreData.tbl_FallOfWicket.hasOwnProperty("createdDate"))是一个数组，因此此条件将始终返回false。因此，matchScoreData.tbl_FallOfWicket永远不会执行。

您将不得不检查单个对象。

delete['...']

演示：

if (element.hasOwnProperty("createdDate"))

Answer 2

以下工作，在这里，如果您的条件是指原始对象，但是您应该使用当前元素，在这种情况下，您需要使用删除element [“ yourkey”]。

下面是适合您的JS。

var data = matchScoreData.tbl_FallOfWicket;
    matchScoreData.tbl_FallOfWicket.forEach(element => {
      if (element.hasOwnProperty("createdDate")) {
        delete element["createdDate"];
      }
    });
    console.table(data);

Answer 3

必须为delete element.createDate（与其他任何属性相同）

var matchScoreData = {

  "tbl_FallOfWicket": [{
      "pk_fallWicketID": 119,
      "fk_matchID": 133137,
      "fk_teamID": 141065,
      "fk_dismissTypeID": 3,
      "fk_dismissPlayerID": 969155,
      "run": 40,
      "wicket": 1,
      "over": "5.1",
      "inning": 1,
      "createdDate": "2018-08-18T03:06:12+0000",
      "modifiedDate": "",
    },
    {
      "pk_fallWicketID": 120,
      "fk_matchID": 133137,
      "fk_teamID": 141065,
      "fk_dismissTypeID": 1,
      "fk_dismissPlayerID": 939721,
      "run": 88,
      "wicket": 2,
      "over": "9.5",
      "createdDate": "2018-08-18T03:06:12+0000",
      "modifiedDate": "",
      "inning": 1
    }
  ]
};

var data = matchScoreData.tbl_FallOfWicket;
matchScoreData.tbl_FallOfWicket.forEach(element => {
  if (element.hasOwnProperty("createdDate")) {
    delete element.createdDate;
  }
});
console.log(data);

Answer 4

这有效

var matchScoreData = {
  tbl_FallOfWicket: [
    {
      pk_fallWicketID: 119,
      fk_matchID: 133137,
      fk_teamID: 141065,
      fk_dismissTypeID: 3,
      fk_dismissPlayerID: 969155,
      run: 40,
      wicket: 1,
      over: "5.1",
      inning: 1,
      createdDate: "2018-08-18T03:06:12+0000",
      modifiedDate: ""
    },
    {
      pk_fallWicketID: 120,
      fk_matchID: 133137,
      fk_teamID: 141065,
      fk_dismissTypeID: 1,
      fk_dismissPlayerID: 939721,
      run: 88,
      wicket: 2,
      over: "9.5",
      createdDate: "2018-08-18T03:06:12+0000",
      modifiedDate: "",
      inning: 1
    }
  ]
};

for(let i=0;i<matchScoreData.tbl_FallOfWicket.length;i++){
    delete matchScoreData.tbl_FallOfWicket[i].createdDate;
    delete matchScoreData.tbl_FallOfWicket[i].modifiedDate;
}

console.log(matchScoreData);

Answer 5

由于您始终将输出分配给新变量，因此可以使用map和一些destructuring。

var matchScoreData = {"tbl_FallOfWicket":[{"pk_fallWicketID":119,"fk_matchID":133137,"fk_teamID":141065,"fk_dismissTypeID":3,"fk_dismissPlayerID":969155,"run":40,"wicket":1,"over":"5.1","inning":1,"createdDate":"2018-08-18T03:06:12+0000","modifiedDate":""},{"pk_fallWicketID":120,"fk_matchID":133137,"fk_teamID":141065,"fk_dismissTypeID":1,"fk_dismissPlayerID":939721,"run":88,"wicket":2,"over":"9.5","createdDate":"2018-08-18T03:06:12+0000","modifiedDate":"","inning":1}]};

const data = matchScoreData.tbl_FallOfWicket.map(obj => {

  // pluck out the dates and assign the rest of the properties
  // to "rest", then simply return those properties
  const { createdDate, modifiedDate, ...rest } = obj;
  return rest;
});

console.log(data);

如何删除数组不同对象中的相似键

5 个答案: