Question

我有一个如下字典数组：

    {
        "photo_id" = 255025344921316;
        "photo_url" = "https://scontent.xx.fbcdn.net/v/t1.0-0/p320x320/16143181_255025344921316_6580634265541865230_n.jpg?oh=4f6359dbc63241c9dfab29c8cfc570ef&oe=598E85AE";
    },

        {
        "photo_id" = 255024861588031;
        "photo_url" = "https://scontent.xx.fbcdn.net/v/t1.0-0/p75x225/16106022_255024861588031_911227627582642933_n.jpg?oh=0bc3fb9df0ccac44c9bd03e8ee1a407d&oe=597A199C";
    },

        {
        "photo_id" = 255024731588044;
        "photo_url" = "https://scontent.xx.fbcdn.net/v/t1.0-0/p320x320/16113986_255024731588044_6834401222098779590_n.jpg?oh=68b39d59c803e30754fa6aaab5ea3017&oe=598A3425";
    }

现在我要删除包含＆＃34; photo_id的对象：255024731588044＆＃34;

我该怎么做？

Answer 1

您可以使用执行.index(where:)执行的0(n)方法获取要删除的字典的索引：

let index = array.index(where: { dictionary in
  guard let value = dictionary["photo_id"] as? Int
    else { return false }      
  return value == 255024731588044
})

如果不是index：

，您可以使用nil值将其删除

if let index = index {
  array.remove(at: index)
}

在这里你可以download操场。

Answer 2

假设数组类型为Animal，您可以使用过滤器删除特定值。尝试这样做

[[String:Any]]

Answer 3

试试这个：

let searchedPhotoID = 255024731588044
guard let index = arrayOfDict.index(where: {
    guard let photoID = $0["photo_id"] as? Int else { return false }
    return photoID == searchedPhotoID
}) else {
    return // photoID not found - handle somehow
}
arrayOfDict.remove(at: index)

如何使用键值删除字典数组中的对象

3 个答案: