Question

我有以下脚本，我只想过滤包含in语句的分析师的结果：

select count(distinct t1.ticketid),t2.BuilderAnalystID AS iDS
from ticket as t1 inner join
Timepoint as t2 on t1.ticketid=t2.TicketID
 where 
     (InternalTicketStatusID=4 and
     (TicketStatus like '%closed%' or ticketstatus like '%resolved%'))
     or
     (InternalTicketStatusID<>4 and
     (TicketStatus like '%closed%' or ticketstatus like '%resolved%')) AND
     SubmissionToDT>='04-01-2017' AND
     SubmissionToDT<='07-12-2019' AND
     (t2.BuilderAnalystID not like null
      and t2.BuilderAnalystID in (1,3,8,9,10,11,12,13,14,15,186,193,233,234,235,236,237,238))
      group by t2.BuilderAnalystID

但是，在返回的结果中，我看到的是所有分析师的ID，而不是我包含在IN语句中的ID。我也看到null的ID！任何线索为什么会这样？谢谢

Answer 1

如果一致地格式化代码，您将立即发现问题：

where (InternalTicketStatusID = 4 and
       (TicketStatus like '%closed%' or ticketstatus like '%resolved%'
       )
      ) or
--------^  Alert!  The following conditions do not apply
      (InternalTicketStatusID <> 4 and
       (TicketStatus like '%closed%' or ticketstatus like '%resolved%'
       )
      ) AND
      SubmissionToDT >= '2017-04-01' AND
      SubmissionToDT <= '2019-07-12' AND
      (t2.BuilderAnalystID not like null and
       t2.BuilderAnalystID in (1,3,8,9,10,11,12,13,14,15,186,193,233,234,235,236,237,238)
      )

您的第一个条件（在括号中）未与其他条件连接。括号关闭了。

这就是为什么我用右括号将右括号匹配。

我还固定了日期常量。

Answer 2

t2.BuilderAnalystID not like null产生null而不是true
并且在where子句中，只有true和false响应才是逻辑运算

您是说

AND  ( t2.BuilderAnalystID is not  null

   and t2.BuilderAnalystID in (1,3,8,9,10,11,12,13,14,15,186,193,233,234,235,236,237,238))

或更佳

AND  t2.BuilderAnalystID in (1,3,8,9,10,11,12,13,14,15,186,193,233,234,235,236,237,238)

IN不充当OR

2 个答案: