Question

原谅标题，我不知道该怎么称呼它。所以想象一下我有这个

table_ref

id_x|id_y
---------
6|70
6|71
6|72
6|73
8|70
8|73
9|72
9|73

如果id_y与id_x= 6 & 8 & 9匹配，我该如何选择？{1}}？在这种情况下，它应该返回73

然后将id_y的返回结果用作另一个SQL查询中的内部联接。

Answer 1

当然，很难进行参数化，但如果它很重要，那么你可以将这些值作为表值参数传递。

SELECT T.id_y
FROM table_ref T
  JOIN (VALUES (6), (8), (9)) A(id_x)
    ON T.id_x = A.id_x
GROUP BY T.id_y
HAVING COUNT(*) = 3

Answer 2

SELECT distinct [idy] 
FROM Table_1
WHERE idy in (SELECT idy FROM Table_1 WHERE idx=6)
AND idy in (SELECT idy FROM Table_1 WHERE idx=8)
AND idy in (SELECT idy FROM Table_1 WHERE idx=9)

Answer 3

请试试这个：

select a.* from  table_ref as a
inner join table_ref as b 
        on a.id_y = b.id_y
        and b.id_x = 8
inner join table_ref as c
        on a.id_y = c.id_y
        and c.id_x = 9
where a.id_x = 6

Answer 4

是的，您可以使用普通的IN来实现：

sqlite> SELECT * FROM table_ref;
6|70
6|71
6|72
6|73
8|70
8|73
9|72
9|73
sqlite> SELECT id_y
...> FROM table_ref t
...> WHERE id_x IN (6,8,9)
...> GROUP BY t.id_y
...> HAVING COUNT(*) = 3;
73

Answer 5

即使在SQL-Server 2005上也是如此。

您可以使用多个EXIST s：

SELECT DISTINCT  t.id_y
FROM dbo.table_ref t
WHERE EXISTS(
   SELECT 1 FROM dbo.table_ref t2
   WHERE t2.id_y=t.id_y AND t2.id_x = 6
)
AND EXISTS(
   SELECT 1 FROM dbo.table_ref t2
   WHERE t2.id_y=t.id_y AND t2.id_x = 8
)
AND EXISTS(
   SELECT 1 FROM dbo.table_ref t2
   WHERE t2.id_y=t.id_y AND t2.id_x = 9
)

Demo

这看起来不太好但是它的工作效率和适当的指数都很有效。

Answer 6

使用内部联接：

SELECT a.id_y
FROM
  (SELECT id_x, id_y 
   FROM table_ref 
   WHERE id_x =6 )a INNER JOIN
  (SELECT  id_x, id_y 
   FROM table_ref 
   WHERE id_x =8)b on a.id_y = b.id_y
 INNER JOIN
 (SELECT id_x, id_y 
  FROM table_ref  
  WHERE id_x =9)c on b.id_y = c.id_y

演示：http://sqlfiddle.com/#!3/28bcb/6

Answer 7

这应该有效：

SELECT          [id_y]
FROM            [table_ref]
WHERE           [id_x] IN (6, 8, 9)
GROUP BY        [id_y]
HAVING          Count(DISTINCT [id_x]) = 3

如果您想从单独的表中获取值范围，可以使用以下方法获取：

DECLARE @Lookup TABLE (ID INT)
INSERT INTO @Lookup VALUES (6), (8), (9)

SELECT          [id_y]
FROM            [table_ref] 
WHERE           [id_x] IN (SELECT [ID] FROM @Lookup)
GROUP BY        [id_y]
HAVING          Count(DISTINCT [id_x]) = (SELECT Count(DISTINCT [ID]) FROM @Lookup)

Answer 8

如果你想要一些更通用的东西：

SELECT   id_y
FROM     table_ref
GROUP BY id_y
WHERE    COUNT(DISTINCT id_x)) = (SELECT COUNT(DISTINCT id_x)) FROM table_ref)

它只返回与表中每个id_x关联的id_y的值，而不管id_x的数量

Answer 9

这个怎么样？

Select blah
From OtherTable
Where id_y in ( Select id_y from table_ref where id_x in (6,8,9))

SQL查询在哪里＆＃39; IN＆＃39;充当＆＃39; AND＆＃39;不是＆＃39;或者＆＃39;？

9 个答案: