Question

尝试使用嵌套在子对象结构中的值映射对象数组：

{
"Version": "2012-10-17",
"Statement": [
    {
        "Effect": "Allow",
        "Principal": {
            "Service": "batchoperations.s3.amazonaws.com"
        },
        "Action": "sts:AssumeRole"
    }
]}

结构如下：

const objs = [{
        "B": {
            "value": 1,
        },
        "D": {
            "value": "45"
        },
        "E": {
            "value": "234"
        },
        "A": {
            "value": "543"
        },
        "C": {
            "value": "250"
        }
    },...]

，映射结果为[ { name: 'B', value: 1 }, { name: 'D', value: '45' }, { name: 'E', value: '234' }, { name: 'A', value: '543' }, { name: 'C', value: '250' } ]

undefined

示例：Stackblitz

Answer 1

return在Object.keys中丢失。同样，也可以使用Object.keys代替Object.entries来获取key和value。

const objs = [{
  "B": {
    "value": 1,
  },
  "D": {
    "value": "45"
  },
  "E": {
    "value": "234"
  },
  "A": {
    "value": "543"
  },
  "C": {
    "value": "250"
  }
}];
const mapped = objs.map((key, _) => {
  return Object.entries((key)).map(([name, {
    value
  }]) => ({
    name,
    value
  }))
}).flat();

console.log(mapped);

Answer 2

您缺少return语句和value属性定义。

此外，您可能希望使用flatMap而不是map以避免结果中出现嵌套数组：

const objs = [{
    "B": {
        "value": 1,
    },
    "D": {
        "value": "45"
    },
    "E": {
        "value": "234"
    },
    "A": {
        "value": "543"
    },
    "C": {
        "value": "250"
    }
}]

const mapped = objs.flatMap((key, index) => {
    return Object.keys(key).map(el => ({
        name: el,
        value: key[el].value
    }))
})

console.log(mapped)

Answer 3

您应该对objs [0]而不是objs进行操作，因为它是一个对象的数组，而不是对象的数组。

let array = []
for(let object in objs[0]){
array.push({
"name": object,
"value": objs[0][object].value
})
}

javascript无法映射具有嵌套值的对象数组

3 个答案: