无效的参数=值“ 2”对于“索引”无效，参数名称：索引

Question

希望大家都很好，我需要一些帮助，我需要更新一些文本框和listview项，我已经成功更新了文本框，但listview项保持不变，我想在更新时添加listview行，希望您理解我担心的请在这里提出一些想法是我的更新按钮代码

 private void btnUpdate_Click_1(object sender, EventArgs e)
        {
             try
            {
                con = new SqlConnection(cs.DBConn);
                con.Open();
                String cb = "update Invoice_info set  VATPer='" + txtTaxPer.Text + "',VATAmount='" + txttableno.Text + "',DiscountPer='" + txtDiscountPer.Text + "',DiscountAmount='" + txtDiscountAmount.Text + "',GrandTotal= '" + txtTotal.Text + "',TotalPayment= '" + txtTotalPayment.Text + "',PaymentDue= '" + txtPaymentDue.Text + "',Remarks='" + txtCustomerName.Text + "' where Invoiceno= '" + txtInvoiceNo.Text + "'";
                cmd = new SqlCommand(cb);
                cmd.Connection = con;
                cmd.ExecuteReader();
                con.Close();
                for (int i = 0; i <= ListView1.Items.Count ; i++)
                {
                    con = new SqlConnection(cs.DBConn);
                    string cd = "insert Into ProductSold(InvoiceNo,ProductID,ProductName,Quantity,Price,TotalAmount) VALUES (@d1,@d2,@d3,@d4,@d5,@d6)";
                    cmd = new SqlCommand(cd);
                    cmd.Connection = con;
                    cmd.Parameters.AddWithValue("d1", txtInvoiceNo.Text);
                    cmd.Parameters.AddWithValue("d2", ListView1.Items[i].SubItems[1].Text);
                    cmd.Parameters.AddWithValue("d3", ListView1.Items[i].SubItems[2].Text);
                    cmd.Parameters.AddWithValue("d4", ListView1.Items[i].SubItems[4].Text);
                    cmd.Parameters.AddWithValue("d5", ListView1.Items[i].SubItems[3].Text);
                    cmd.Parameters.AddWithValue("d6", ListView1.Items[i].SubItems[5].Text);
                    con.Open();
                    cmd.ExecuteNonQuery();
                    con.Close();
                }

                btnUpdate.Enabled = true ;
                MessageBox.Show("Successfully updated", "Record", MessageBoxButtons.OK, MessageBoxIcon.Information);
            }
            catch (Exception ex)
            {
                MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
            }
        }

我在标题中显示了相同的错误