InvalidArgument =' 3'的值对于' index'无效。参数名称:索引

时间:2015-09-02 17:11:58

标签: c# mysql

我的代码中出现此错误: InvalidArgument =' 3'的值对于' index'无效。参数名称:索引,  当我想填写我的listview的一部分时! 这是我的代码:

 MySqlCommand cmd = new MySqlCommand("select acc_Id,acc_Name,acc_Place from accounts where archived=0 and  cus_Sup=" + 0 , objConn);
                    MySqlDataReader dataReader = cmd.ExecuteReader();
                    int i = 0;
                    while (dataReader.Read())
                    {
                        if (i % 2 == 0)
                            listView2.Items.Add(dataReader.GetValue(0).ToString()).BackColor = Color.Lavender;
                        else
                            listView2.Items.Add(dataReader.GetValue(0).ToString());

                        listView2.Items[i].SubItems.Add(dataReader.GetString(1).ToString());

                        listView2.Items[i].SubItems.Add((dataReader.IsDBNull(2) ? "No place added" : dataReader.GetString(2)));
                        //------------------------------------I meant here !
                        listView2.Items[i].SubItems.Add("0");
                        listView2.Items[i].SubItems.Add("0");
                        listView2.Items[i].SubItems.Add("0");

                    }
                    dataReader.Close();


                    //-------------load bills
                    for (int x = 0; x < listView2.Items.Count; x++)
                    {
                        cmd = new MySqlCommand("select c.acc_Id,a.bill_Number,a.bill_Date,c.acc_Name,Sum( (b.de_Quantity * b.de_Price) - ((b.de_Quantity * b.de_Price)*b.de_DisRate/100) ),a.bill_TaxRate,a.bill_DisRate,a.bill_Note,c.acc_Place from (accounts c right JOIN bills a on c.acc_Id = a.bill_From) LEFT JOIN  bill_Details b on a.bill_Id = b.bill_Id where c.acc_Id = " + listView2.Items[x].SubItems[0].Text + " group by a.bill_Id,a.bill_Number,a.bill_Date,c.acc_Name,a.bill_TaxRate,a.bill_DisRate,a.bill_Note,c.acc_Place ", objConn);
                        dataReader = cmd.ExecuteReader();

                        decimal totalSum = 0, summBills = 0;
                        i = 0;
                        while (dataReader.Read())
                        {

                            totalSum = decimal.Parse(dataReader.IsDBNull(4) ? "0" : dataReader.GetDecimal(4).ToString("n2"));
                            totalSum -= (totalSum * decimal.Parse(dataReader.IsDBNull(6) ? "0" : dataReader.GetDecimal(6).ToString("n2")) / 100);
                            totalSum += (totalSum * decimal.Parse(dataReader.IsDBNull(5) ? "0" : dataReader.GetDecimal(5).ToString("n2")) / 100);
                            summBills += totalSum;
                            i++;
                        }
                        //MessageBox.Show(dataReader.GetValue(0).ToString()+"   "+summBills.ToString());
                        listView2.Items[x].SubItems[3].Text = summBills.ToString("n2");// the error here !

                        dataReader.Close();

                    }

它只打印第一张唱片的价值! ,当它移动到第二个时出现错误!

1 个答案:

答案 0 :(得分:1)

您已为每个ListView项添加了3个子项。它们将是Items [x] .SubItems [0]到SubItems [2]。您需要添加4个SubItem才能使用SubItem [3]。

编辑:

当您在顶部循环中添加项目时,您不会递增i - 您需要将顶部循环更改为:

            int i = 0;
            while (dataReader.Read())
            {
                if (i % 2 == 0)
                    listView2.Items.Add(dataReader.GetValue(0).ToString()).BackColor = Color.Lavender;
                else
                    listView2.Items.Add(dataReader.GetValue(0).ToString());

                listView2.Items[i].SubItems.Add(dataReader.GetString(1).ToString());

                listView2.Items[i].SubItems.Add((dataReader.IsDBNull(2) ? "No place added" : dataReader.GetString(2)));
                //------------------------------------I meant here !
                listView2.Items[i].SubItems.Add("0");
                listView2.Items[i].SubItems.Add("0");
                listView2.Items[i].SubItems.Add("0");

                i++;
            }
            dataReader.Close();

如果没有这个,你每次都会向ListView添加一个新的Item,但每次都会将listItems添加到listView2.Items [0]。这就是为什么第二个失败的原因。 Items [0]有5个子项的多个,其余的没有。