根据Python中的某些值拆分列表？

Question

我有3个列表，

a = ['Good', '24.97 %']
b = ['Bad', '75.03 %']
c = [('Amount', 0.20),
     ('Decision1', -0.149),
     ('Unit', 0.128),
     ('Decision2', -0.120),
     ('Decision3', 0.038),
     ('Matches', 0.016)]

好的对应于列表c中的负值，不好的对应于列表c中的值，所以我必须将其分离到一个新的列表中，例如

Good = ['Good', '24.97 %', ('Decision1', -0.149), ('Decision2', -0.120)]

Bad = ['Bad', '75.03 %', ('Amount', 0.20),('Unit', 0.128),('Decision3', 0.038),
     ('Matches', 0.016)]

Answer 1

使用列表理解来获取底片和底片并将其附加到其他列表中：

good = a + [x for x in c if x[1] < 0]
bad = b + [x for x in c if x[1] > 0]

Answer 2

使用以下代码获取结果：-

a = ['Good', '24.97 %']
b = ['Bad', '75.03 %']
c = [('Amount', 0.20),
 ('Decision1', -0.149),
 ('Unit', 0.128),
 ('Decision2', -0.120),
 ('Decision3', 0.038),
 ('Matches', 0.016)]

good = a.copy()
bad = b.copy()
for var in c:
    if var[1] < 0:
        good.append(var)
    else:
        bad.append(var)
print(good)
print(bad)

输出

['Good', '24.97 %', ('Decision1', -0.149), ('Decision2', -0.12)]
['Bad', '75.03 %', ('Amount', 0.2), ('Unit', 0.128), ('Decision3', 0.038), ('Matches', 0.016)]

希望对您有帮助。