如何在创建路线中找到我的错误?

时间:2019-07-11 20:58:06

标签: javascript jquery mysql ajax typescript

任务是从html开始,通过客户端打字稿和服务器打字稿为我的sql数据库编写一条用于用户注册的创建路由。我什至不知道该错误是否出在我的客户端或服务器上。

我已经尝试使用控制台和调试器对其进行调试。运行服务器可以正常工作,而加载.js也可以。因此,我认为错误必定是在client.ts上的功能或者在server.ts上的功能/路由(或者可能是两者)上。

client.ts

    function registrierung(event: Event): void {
        event.preventDefault();

        const vnamex: string = vname.val().toString();
        const nnamex: string = nname.val().toString();
        const strassex: string = strasse.val().toString();
        const hnrx: string = hnr.val().toString();
        const plzx: string = plz.val().toString();
        const ortx: string = ort.val().toString();
        const emailx: string = email.val().toString();
        const passwortx: string = passwort.val().toString();

     $.ajax({
                   contentType: "application/x-www-form-urlencoded",
                   data: "vname=" + vnamex + "&nname=" + nnamex +
        "&strasse=" + strassex + "&hnr=" + hnrx + "&plz=" + plzx + "&ort=" + ortx +
        "&email=" + emailx + "&passwort=" + passwortx,

        type: "POST",
        url: "/register",
    });
    }

server.ts

    const createQuery: string = "INSERT INTO person" + "(vname, nname, strasse, hnr, plz, ort, email, passwort) VALUES (?, ?, ?, ?, ?, ?, ?, ?);";

    router.post("/register", regserver);

    function regserver(req: express.Request, res: express.Response) {

        const vname: string = req.body.vname;
        const nname: string = req.body.nname;
        const strasse: string = req.body.strasse;
        const hnr: string = req.body.hnr;
        const plz: string = req.body.plz;
        const ort: string = req.body.ort;
        const email: string = req.body.email;
        const passwort: string = req.body.passwort;

       connection.query(createQuery, [vname, nname, strasse, hnr, plz, ort, email, passwort],
            (err: mysql.MysqlError | null) => {
                if (err === null) {
                    res.sendStatus(201);
                } else {
                    res.sendStatus(500);
                }
            });
    }

因此,来自html输入字段的数据应在sql表“ person”中创建新行。

0 个答案:

没有答案