Question

我正在尝试制定用于优化日常任务计划的算法。例如：

1. There are 16 tasks to finish in one day, expirience worker can finish 8 tasks and newer worker could finish 4 tasks. As output we should get 2 expirienced worker and none new worker.

现在我有以下代码，但无法正常工作：

private void calculate(int numberOfTasks, int oldWorkerValue, int youngWorkerValue) {

    int numberOfOldWorkers = numberOfTasks / oldWorkerValue;
    int numberOfYoungWorkers = 0;

    if(numberOfOldWorkers == 0) {
        numberOfOldWorkers = 1;
    } else {
        numberOfYoungWorkers = (numberOfTasks % numberOfOldWorkers) / youngWorkerValue;

        if(numberOfTasks % oldWorkerValue != youngWorkerValue*numberOfYoungWorkers) {
            numberOfYoungWorkers = numberOfYoungWorkers + 1;
        }
    }
    System.out.println("Expirienced worker: " + numberOfOldWorkers + " and new workers: " + numberOfYoungWorkers);
}

它返回了我的工人人数，但是却无法正常工作。我没有像在这几个示例中写的那样得到结果。你能给我一些建议吗？

Answer 1

我不确定您是否可以找到确切的公式，所以我会做简单的暴力破解：

public static Pair<Integer, Integer> calculate(int numberOfTasks, int oldWorkerValue, int youngWorkerValue) {
    int m = Integer.MAX_VALUE; // minimal value
    int o = 0; // old workers
    int n = 0; // new workers
    for (int i = 1; i <= (int)Math.ceil((double) numberOfTasks / oldWorkerValue); i++) {
        int nw = (int) Math.ceil((double)(numberOfTasks - i * oldWorkerValue) / youngWorkerValue);
        if (nw < 0) nw = 0;
        int tm = i * oldWorkerValue + nw * youngWorkerValue;
        if (tm < m) {
            m = tm; o = i; n = nw;
        }
    }
    return new Pair<>(o, n); // pair <old workers, new workers>
}

高效优化算法

1 个答案: