Question

我创建了以下查询，从周六和周日开始每隔7天重复一次。该报告将每七天运行一次。但是，在我们的SFTP文件夹（入站）报告中收到文件的那天，我面临的问题应该是缺少Null = 0的条目。使此自动化过程的主要目标是每个星期日都将执行每七天星期日示例：

SELECT SubmitterID,SubmitterName,convert(varchar(15), DateReceived, 101) DateReceived,sum(ClaimCount) as TotalCount
FROM FalloutClaimReport
WHERE DateReceived BETWEEN '2019-06-01' AND '2019-06-07'
--ORDER BY COUNT(submitterID) DESC;
GROUP BY submitterid, SubmitterName, convert(varchar(15), DateReceived, 101)

DECLARE @StartDate AS DATETIME
DECLARE @EndDate AS DATETIME
DECLARE @CurrentDate AS DATETIME

SET @StartDate = '2019-06-01' --AND '2019-06-10'
SET @StartDate = '2019-06-07'
SET @EndDate = GETDATE()
SET @CurrentDate = @StartDate

Answer 1

我不确定您在寻找什么，但是我认为一般的方法是您试图获取一周的数据。

日期计算

让我们从一些查询开始（这些查询假定美国安装为默认日期为星期一。

SELECT
    DATEADD(WEEK, -1, CAST(DATEADD(WEEK, DATEDIFF(WEEK, 0, CAST(GETDATE() AS date)), -1) AS date)) AS TheLastSundayOfTheFullWeek
,   DATEADD(WEEK, -1, CAST(DATEADD(WEEK, DATEDIFF(WEEK, 0, CAST(GETDATE() AS date)), +5) AS date)) AS TheLastSaturdayOfTheFullWeek
,   CAST(DATEADD(WEEK, DATEDIFF(WEEK, 0, CAST(GETDATE() AS date)), -1) AS date) AS SundayOfTheCurrentWeek
,   CAST(DATEADD(WEEK, DATEDIFF(WEEK, 0, CAST(GETDATE() AS date)), +5) AS date) AS SaturdayOfTheCurrentWeek;

这些查询生成以下日期

TheLastSundayOfTheFullWeek TheLastSaturdayOfTheFullWeek SundayOfTheCurrentWeek SaturdayOfTheCurrentWeek
2019-06-30                 2019-07-06                   2019-07-07             2019-07-13

最后一整周的运行时间为6/30至7/06。当前一周将定义为7/7至7/13。

根据您需要的星期定义，选择合适的两列。

应对未知事物

在这种情况下，我构建了一个虚拟表，其中包含报告应具有的所有预期日期（或元素）。然后，我用它来驱动到实际数据表的连接。由于我们不知道给定日期会找到任何行，因此我将这些表与LEFT JOIN连接起来

SELECT
    FCR.SubmitterID
,   FCR.SubmitterName
,   CONVERT(varchar(15), ED.DateReceived, 101) AS DateReceived
,   SUM(FCR.ClaimCount) AS TotalCount
FROM
    (
        -- This logic builds out a list of all the dates that must exist on the report
        -- I used the logic for TheLastSundayOfTheFullWeek
        SELECT
            DATEADD(DAY, D.DayOffset, DATEADD(WEEK, -1, CAST(DATEADD(WEEK, DATEDIFF(WEEK, 0, CAST(GETDATE() AS date)), -1) AS date))) AS DateReceived
        FROM
        (
            -- Generate a series of 7 numbers from 0 t 6
            SELECT TOP 7
                -1 + ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) AS rn
            FROM
                sys.all_columns AS AC 
        ) D(DayOffset)
    ) AS ED
    LEFT OUTER JOIN
        dbo.FalloutClaimReport AS FCR
        ON FCR.DateReceived = ED.DateReceived
GROUP BY
    CONVERT(varchar(15), ED.DateReceived, 101)
,   FCR.SubmitterID
,   FCR.SubmitterName;

生成的结果集如下

我们在30号或5号没有数据，但查询中仍然有记录。如果您需要在其中使用默认值，请使用ISNULL / COALESCE调用包装该列。

DBFiddle version提供测试沙箱

Answer 2

奥黛丽，

我会提出两种可能的解决方案。假设您指的是SRS，SSRS。...

1）我将您的SSIS作业设置为每7天通过SQL代理运行一次。它将调用存储过程（SP），然后运行该存储过程并将其写入表中……当调用该SP时，它将运行：

SELECT 
SubmitterID,
SubmitterName,
convert(varchar(15), DateReceived, 101) DateReceived,
sum(ClaimCount) as TotalCount
FROM FalloutClaimReport
WHERE cast(DateReceived as date) BETWEEN dateadd(d,-7,cast(getdate() as date)) AND dateadd(d,-1,cast(getdate() as date))

GROUP BY 
submitterid,
SubmitterName,
convert(varchar(15), DateReceived, 101)

2）如果您决定采用SSRS路由，则应进行报告订阅，该报告订阅会自动发送给您需要的用户，该用户调用上面的存储过程，并将需要的信息发送给需要它的任何人。（上面的代码应该足以假设它正在选择所需的内容）

SQL-每周报告，为期7天（星期日至星期六）

2 个答案:

日期计算

应对未知事物