Question

我需要写一个proc，如果我的实际日期超过3天，我需要更新ACTUAL_FINISH日期。这三天不会考虑周六周日。

select *
from MILESTONE_SCHEDULE
WHERE MILESTONE_TYPE_ID = 398
  and ACTUAL_FINISH IS NULL
  AND ACTUAL_START IS NOT NULL;

Answer 1

假设您的MILESTONE_SCHEDULE表格中有唯一的ID，为了达到您所寻找的目标，您可以尝试以下内容。

UPDATE T
SET ACTUAL_FINISH = GETDATE()--or whatever you want
FROM MILESTONE_SCHEDULE T
INNER JOIN
(    
   SELECT ID,
   (DATEDIFF(dd, ACTUAL_START, GETDATE()) )
  -(DATEDIFF(wk, ACTUAL_START, GETDATE()) * 2)
  -(CASE WHEN DATENAME(dw, ACTUAL_START) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, GETDATE()) = 'Saturday' THEN 1 ELSE 0 END) AS DayDif
  FROM MILESTONE_SCHEDULE T
  ) T1
  ON T1.ID= T.ID
WHERE T1.DayDif > 3
AND T.MILESTONE_TYPE_ID = 398
AND T.ACTUAL_FINISH IS NULL
AND T.ACTUAL_START IS NOT NULL;

使用虚拟数据的示例

以下查询将有助于更新值。

DECLARE @MILESTONE_SCHEDULE TABLE(ID INT ,ACTUAL_START DATETIME ,ACTUAL_FINISH DATETIME)

INSERT INTO @MILESTONE_SCHEDULE
VALUES(1,GETDATE()-10,NULL),(2,GETDATE(),NULL)     

UPDATE T
SET ACTUAL_FINISH = GETDATE()
FROM @MILESTONE_SCHEDULE T
INNER JOIN
(    
   SELECT ID,
   (DATEDIFF(dd, ACTUAL_START, GETDATE()) )
  -(DATEDIFF(wk, ACTUAL_START, GETDATE()) * 2)
  -(CASE WHEN DATENAME(dw, ACTUAL_START) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, GETDATE()) = 'Saturday' THEN 1 ELSE 0 END) AS DayDif
  FROM @MILESTONE_SCHEDULE T
  ) T1
  ON T1.ID= T.ID
WHERE T1.DayDif > 3

SELECT * FROM @MILESTONE_SCHEDULE

<强>输出：

ID  ACTUAL_START                ACTUAL_FINISH
1   2018-03-02 11:26:25.707     2018-03-12 11:26:25.707
2   2018-03-12 11:26:25.707     NULL

日期之间的差异sql-忽略周六周日

1 个答案: