Question

这是我的对象数组。我想通过在函数中传递查询来过滤对象。

const products = [{
    name: "A",
    color: "Blue",
    size: 50
  },
  {
    name: "B",
    color: "Blue",
    size: 60
  },
  {
    name: "C",
    color: "Black",
    size: 70
  },
  {
    name: "D",
    color: "Green",
    size: 50
  }
];

我想要的输出将从我传递的查询中过滤出来，该查询可以是任何东西

{
  name: "A",
  color: "Blue",
  size: 50
}, {
  name: "C",
  color: "Black",
  size: 70
}

这是我要传递给函数的查询对象

const filter = {
  color: ["Blue", "Black"],
  size: [70, 50]
};

这是我的函数，可以将其分配给其他变量并将其用于进一步的操作

const filteredData = filterIt(products, filter);

Answer 1

您可以获取过滤器对象的条目，并获取用于通过includes检查的键和值。

const
    filterBy = filter => o => Object.entries(filter).every(([k, v]) => v.includes(o[k])),
    filterIt = (array, filter) => array.filter(filterBy(filter)),
    products = [{ name: "A", color: "Blue", size: 50 }, { name: "B", color: "Blue", size: 60 }, { name: "C", color: "Black", size: 70 }, { name: "D", color: "Green", size: 50 }],
    filter = { color: ["Blue", "Black"], size: [70, 50] },
    filteredData = filterIt(products, filter);

 console.log(filteredData);

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Answer 2

这是另一种选择：

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      if (filter[k].indexOf(p[k]) === -1) {
        return false;
      }
    }
    return true;
  })
}

查看Demo

如果要在逻辑中使用“或”而不是“与”，则修改的前一个功能将是：

function filterIt(products, filter) {
  return products.filter(p => {
    for (const k in filter) {
      // if a value of any property of the product is contained in a filter array, include it
      if (filter[k].indexOf(p[k]) !== -1) {
        return true;
      }
    }
    return false;
  })
}

为此也请参阅Demo：）

Answer 3

const products = [{
    name: "A",
    color: "Blue",
    size: 50
  },
  {
    name: "B",
    color: "Blue",
    size: 60
  },
  {
    name: "C",
    color: "Black",
    size: 70
  },
  {
    name: "D",
    color: "Green",
    size: 50
  }
];
const filter = {
  color: ["Blue", "Black"],
  size: [70, 50]
};


let filterIt = (products, filter) => {

  return products.filter(p => {
    
    //get all filter keys
    let keys = Object.keys(filter);
    
    let validkeys = [];
    
    keys.forEach(k=>{
      // check if filter property exist and includes filter value
      if(p.hasOwnProperty(k) && filter[k].includes(p[k])){
        validkeys.push(true);
      }
      
    })
    
    //check all filter matches
    return validkeys.length === keys.length;
    
  });

}

const filteredData = filterIt(products, filter);
console.log("...filteredData", filteredData);

通过在javascript中传递键和值从数组中获取对象

3 个答案: