我正在尝试创建一个表,该表显示操作员班次正在合并操作员登录和注销的行。由于存在多个站和运算符,因此我需要根据运算符而不是下一个值选择下一行。例如,在下面将联接的查询分开时,上次登录时间将是第329行,注销时间将是第408行。
登录= 1,注销= 0
select
A.Operator,
A.Station,A.[TIME] AS "Logon",
B.[TIME] AS "Logoff"
from (SELECT
[Operator],
[TIME],
[Station],
ROW_NUMBER() OVER (ORDER BY [TIME], [Operator], Station) AS RowNumber
FROM
shiftstagenew
WHERE [ON-OFF] = '0'
AND [Operator] = 'Operator1') A
JOIN
(SELECT
[Operator],
[TIME],
[Station],
ROW_NUMBER() OVER (ORDER BY [TIME], [Operator], Station) AS RowNumber
FROM shiftstagenew WHERE [ON-OFF] = '1'
AND [Operator] = 'Operator1') B
ON (
A.RowNumber = B.RowNumber
AND
A.Operator = B.Operator
AND
A.Station = B.Station)
我已经更新了查询并且越来越近
select A.Operator, A.Station,B.[TIME] AS "Logon", A.[TIME] AS "Logoff"
from (SELECT [TIME], [Operator], [Station], ROW_NUMBER() OVER (PARTITION
BY
[Operator], [Station] ORDER BY [Time], Station) AS RowNumber
FROM
shiftstagenew WHERE [ON-OFF] = '1') A
JOIN
(SELECT [Time],[Operator], [Station], ROW_NUMBER() OVER (PARTITION BY
[Operator], [Station] ORDER BY [Time], Station) AS RowNumber
FROM shiftstagenew WHERE [ON-OFF] = '0') B
ON (A.Operator=B.Operator AND A.Station=B.Station AND A.RowNumber=B.RowNumber)
Query Results:
Operator Station Logoff Logon
Vitemeus 102 2019-07-07 08:15:19.380 2019-05-27 17:39:06.550
Vitemeus 102 2019-07-07 07:23:54.790 2019-05-27 14:50:13.687
Vitemeus 102 2019-07-07 03:45:46.890 2019-05-27 11:56:54.903
Vitemeus 102 2019-07-07 03:44:28.267 2019-05-24 23:52:49.313
Vitemeus 102 2019-07-07 03:08:16.343 2019-05-20 19:30:11.010
如您所见,上次登录后并没有注销
OFF
2019-07-07 08:15:19.380 Vitemeus 102 445
2019-07-07 07:23:54.790 Vitemeus 102 444
2019-07-07 03:45:46.890 Vitemeus 102 443
2019-07-07 03:44:28.267 Vitemeus 102 442
2019-07-07 03:08:16.343 Vitemeus 102 441
2019-07-07 02:00:09.757 Vitemeus 102 440
2019-07-07 00:37:30.610 Vitemeus 102 439
2019-07-06 13:16:02.330 Vitemeus 102 438
2019-07-06 12:00:19.157 Vitemeus 102 437
ON
2019-07-07 08:02:02.500 Vitemeus 102 498
2019-07-07 06:52:34.303 Vitemeus 102 497
2019-07-07 03:44:42.427 Vitemeus 102 496
2019-07-07 03:25:28.957 Vitemeus 102 495
2019-07-07 02:52:40.210 Vitemeus 102 494
2019-07-07 01:45:00.373 Vitemeus 102 493
2019-07-07 00:32:39.800 Vitemeus 102 492
对于那些要求表结构(ON-OFF为0或1)的人:
CREATE TABLE [dbo].[ShiftStageNEW](
[ON-OFF] [nvarchar](1) NULL,
[Time] [datetime] NULL,
[Station] [nvarchar](3) NULL,
[Action] [nvarchar](4) NULL,
[Operator] [varchar](8) NULL,
[Data] [nvarchar](900) NULL,
[Translation] [int] NULL,
[LogTime] [bigint] NULL,
[MessageId] [nvarchar](256) NULL
) ON [PRIMARY]
答案 0 :(得分:1)
您应该查看LAG
函数:
SELECT
[Year] = YEAR([OrderDate])
,[Sales Amount] = SUM([SalesAmount])
,[Sales Amount Previous Year] = LAG(SUM([SalesAmount])) OVER (ORDER BY YEAR([OrderDate]))
FROM [dbo].[FactResellerSales]
GROUP BY YEAR([OrderDate])
ORDER BY [Year];
来源:https://www.mssqltips.com/sqlservertutorial/9127/sql-server-window-functions-lead-and-lag/
也请在此处查看符合您要求的我的问题:Find next record where status field is different from current
答案 1 :(得分:0)
公用表表达式应该可以帮助您实现所需的目标。
但是行号的排序似乎有点麻烦。
在排序中添加了分区。如果您需要的话,可以坚持使用原始照片。
WITH LOGON AS (
SELECT
[Operator],
[TIME],
[Station],
ROW_NUMBER() OVER (PARTITION BY [Operator], Station ORDER BY [TIME]) AS RowNumber
FROM
shiftstagenew
WHERE
[ON-OFF] = '0'
AND [Operator] = 'Operator1'
),
LOGOFF AS (
SELECT
[Operator],
[TIME],
[Station],
ROW_NUMBER() OVER (PARTITION BY [Operator], Station ORDER BY [TIME]) AS RowNumber
FROM
shiftstagenew
WHERE
[ON-OFF] = '1'
AND [Operator] = 'Operator1'
)
select
LOGON.Operator,
LOGON.Station,
LOGON.[TIME] AS "Logon",
LOGOFF.[TIME] AS "Logoff"
FROM LOGON LEFT JOIN LOGOFF
ON (
LOGON.RowNumber = LOGOFF.RowNumber
AND
LOGON.Operator = LOGOFF.Operator
AND
LOGON.Station = LOGOFF.Station)