Question

列表：

results = [['04-25', [1, 2, 3, 4]], ['04-26', [5, 6, 7, 8]], ['04-27', [9, 20, 11, 21]]

尝试获取此输出：

[['04-25', 1, 2, 3, 4], ['04-26', 5, 6, 7, 8], ['04-27', 9, 20, 11, 21]]

我已经尝试过了：

data = [a for b in [_ for _ in results[i]] for a in b]

将列表中的每个字符分成一个不同的元素，如下所示：

['0', '4', '-', '2', '5', 1, 2, 3, 4]

如何仅访问内部列表并使其扁平化？

Answer 1

use * unpacking：

results = [['04-25', [1, 2, 3, 4]], ['04-26', [5, 6, 7, 8]], ['04-27', [9, 20, 11, 21]]]

data = [[a, *b] for a,b in results]

print(data)

输出：

[['04-25', 1, 2, 3, 4], ['04-26', 5, 6, 7, 8], ['04-27', 9, 20, 11, 21]]

Answer 2

您可以添加第一个值和内部list：

[[i] + j for i, j in results]

输出：

[['04-25', 1, 2, 3, 4], ['04-26', 5, 6, 7, 8], ['04-27', 9, 20, 11, 21]]

Answer 3

尝试此代码！

results = [['04-25', [1, 2, 3, 4]], ['04-26', [5, 6, 7, 8]], ['04-27', [9, 20, 11, 21]]]

for i in range(0,len(results)):
    temp = []
    temp.append(results[i][0])
    for j in range(0,len(results[i][1])):
        temp.append(results[i][1][j])
    results[i] = temp
print(results)

输出：

[['04-25', 1, 2, 3, 4], ['04-26', 5, 6, 7, 8], ['04-27', 9, 20, 11, 21]]

Answer 4

使用extend和append

new_list = []
for item in results:
    new_sublist = []
    for sub_item in item:
        if isinstance(sub_item, list):
            new_sublist.extend(sub_item)
        else:
            new_sublist.append(sub_item)
    new_list.append(new_sublist)
print(new_list)

输出：[['04-25', 1, 2, 3, 4], ['04-26', 5, 6, 7, 8], ['04-27', 9, 20, 11, 21]]

如何只整理内部列表？

4 个答案: