Question

假设我有以下对象列表：

lol = [['When was America discovered by Christopher Colombus?', ['1492', '1510', '1776', '1820'], '1492'], ['What is the name of the school that Harry Potter attends?', ['Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School'], 'Hogwarts'], ['How many colors are there in the common depiction of the rainbow?', ['5', '7', '9', '11'], '7']

我正在尝试弄平内部列表（例如，删除方括号）。结果看起来像

['When was America discovered by Christopher Colombus?', '1492', '1510', '1776', '1820', '1492']

我已经看到了平整整个列表的通用解决方案，例如：

Flattening a shallow list in Python

但是我不知道如何在较大的列表列表中选择性地展平单个列表。

Answer 1

我想您的意思是，您不仅想要显示的输出，还希望在示例输出中另外输出两个。操作方法如下：

lol = [['When was America discovered by Christopher Colombus?', ['1492', '1510', '1776', '1820'], '1492'], ['What is the name of the school that Harry Potter attends?', ['Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School'], 'Hogwarts'], ['How many colors are there in the common depiction of the rainbow?', ['5', '7', '9', '11'], '7']]

r = []
for x in lol:
    r.append([x[0]] + x[1] + [x[2]])

for rr in r:
    print(rr)

结果：

['When was America discovered by Christopher Colombus?', '1492', '1510', '1776', '1820', '1492']
['What is the name of the school that Harry Potter attends?', 'Hogwarts', 'Gryffindor', 'Voldemort', 'Magic School', 'Hogwarts']
['How many colors are there in the common depiction of the rainbow?', '5', '7', '9', '11', '7']

Answer 2

如果您知道如何拼合整个列表，并且想知道仅拼合第一个列表，那么您并不是真正在问如何拼合一个列表，而是在询问如何选择列表中的第一个项目。列表，答案是sublist=lol[0]，然后将其他问题的答案应用于sublist。

展平内部列表中的列表

2 个答案: