Question

我的代码正在读取一个文本文件，该文本文件包含一个用逗号分隔的数字列表。如果有空格和/或制表符，它将检测到它。我的代码运行良好，但是现在我想使它看起来井井有条，并且更好地读取写入的输出文件。

代码：

    import re
    index = 0                                     
    comma_string = ', '
    outfile = "output2.txt"
    wp_string = " White Space Detected"
    tab_string = " tab detected"
    mc_string = " Missing carriage return"
    ne_string = " No Error"
    baconFile = open(outfile,"wt")
    num_lines = 0
    with open("Version2_file.txt", 'r') as f:
        for line in f:               #for loop with variable line defined and using open() function to open the file inside the directory
            flag = 0
            carrera = ""
            index = index +1                            #adds 1 for every line if it finds what the command wants

            print("Line {}: ".format(index))
            baconFile.write("Line {}:  ".format(index) + " ")
            if " " in line:                         #checking for whitespace
                carrera =  wp_string + comma_string + carrera
                flag = 1
                a = 1
            if "\t" in line:                        #checking for tabs return
                carrera =  tab_string + comma_string + carrera
                flag = 1
            if '\n' not in line:
                carrera =  mc_string + comma_string + ne_string + carrera
                flag = 1
            if flag == 0:                           #checking if no error is true by setting flag equal to zero
                carrera = ne_string
            print('\t'.join(str(len(g)) for g in re.findall(r'\d+\.?(\d+)?', line )))
            print (carrera)
            baconFile.write('\t'.join(str(len(g)) for g in re.findall(r'\d+\.?(\d+)?', line ) ))
            baconFile.write(carrera + "\n")    
    with open("Version2_file.txt", 'r') as f:
        content = f.readlines()
        print('Number of Lines: {}'.format(len(content)))
        for i in range(len(content)):
            print('Numbers in Line {}: {}'.format(i+1, len(content[i].split(','))))
            baconFile.write('Numbers in Line {}: {}'.format(i+1, len(content[i].split(','))) + '\n')
        for line in format(len(content)):
            baconFile.write('Number of lines: {}'.format(len(content)) + '\n')
    baconFile.close()

我的文件名文本文件：

1.0,    1.023, 1.45
1.0,1.023,1.45
1

主列：文件名（制表符）行（制表符）数字（制表符）“ sigfigs”的字符串，用逗号（制表符），空格（制表符），制表符（制表符）回车

预期的输出文件：

expected:
```none
Filename    Line    number of numbers    string of “sigfigs/decimal Places” separated by a comma    white space found    tab found    carriage return found    
filename    1            3                       1,3,2                                                    TRUE              FALSE               TRUE        
filename    2            3                       1,3,2                                                    TRUE              FALSE               TRUE
filename    3            1                       1                                                        FALSE             FALSE               FALSE

实际：

Line 1:   1 3   2 tab detected,  White Space Detected, 
Line 2:   1 3   2 No Error
Line 3:   0 Missing carriage return,  No Error
Numbers in Line 1: 3
Numbers in Line 2: 3
Numbers in Line 3: 1
Number of lines: 3

Answer 1

您只需要将所有值保存在表中。处理完文件后，只需遍历循环即可创建一个formatted String，并将其保存在文件中。

要使您的值居中，只需使用符号^，然后在各列之间使用空格。下面我为类似的所需输出示例：

tabled = [
    ['Filename', 'Line', 'number of numbers', 'string separated by a comma', 'white space found', 'tab found', 'carriage return found'],
    ['filename', '1', '3', '1, 3, 2', 'TRUE', 'FALSE', 'TRUE'], 
    ['filename', '2', '3', '1, 3, 2', 'TRUE', 'FALSE', 'TRUE'],
    ['filename', '3', '1', '1', 'FALSE', 'FALSE', 'TRUE']
]

for row in tabled:
    print("{: ^30} {: ^30} {: ^30} {: ^30} {: ^30} {: ^30} {: ^30}".format(*row))

哪个给出输出：

   Filename                         Line                    number of numbers         string separated by a comma         white space found                  tab found                carriage return found     
   filename                          1                              3                           1, 3, 2                          TRUE                          FALSE                           TRUE             
   filename                          2                              3                           1, 3, 2                          TRUE                          FALSE                           TRUE             
   filename                          3                              1                              1                            FALSE                          FALSE                           TRUE

如何在列中重组输出结果

1 个答案: