以下[mcve]将输出两个日期之间的星期数数组。当两个日期都在同一年时,它就可以工作,但是,有些年份有52个星期,并且从去年的最后几天开始。其他人有53周。
2020 calendar是一个52周的例子:
第一个星期从12月30日开始。
53周的示例是2016 calendar:
那只在1月4日开始。
下面的代码被注释并输出包含星期数的数组。
Sub w_test()
Dim Arr() As Variant, ArrDateW() As Variant
'Initial Date
DateI = DateSerial(2015, 5, 5)
'Final Date
DateF = DateSerial(2017, 9, 20)
'Difference in weeks between DateI and DateF
weekDif = DateDiff("ww", DateI, DateF) + k - 1
i = Weekday(DateI)
d = DateI
'If not Sunday, go back to last week, to start the loop
If i <> 1 Then
d = DateAdd("d", -(i - 1), d)
End If
ReDim ArrDateW(weekDif)
ReDim Arr(2)
'Loop on all weeks between two dates to populate array of arrays
For i = 0 To weekDif
'Date
Arr(0) = d
'Trying to solve problem with New Year
If Application.WorksheetFunction.WeekNum(d) = 53 Then
flag = True
End If
If flag = False Then
Arr(1) = Application.WorksheetFunction.WeekNum(d)
Else
Arr(1) = Application.WorksheetFunction.WeekNum(DateSerial(Year(d) + 1, 1, 1))
flag = False
End If
'Year
Arr(2) = Year(d)
'Populate array of arrays
ArrDateW(i) = Arr
'Next Week Number
d = DateAdd("ww", 1, d)
Next i
'To stop with Ctrl+F8
Debug.Print d
End Sub
2015年有53周,但是程序输出以下内容:
在2016 and 2017之间,输出是一团糟:
答案 0 :(得分:1)
我依靠内置的VBA函数正确地计算周数,因此处理方式有所不同。了解有关ISO周数的信息是this answer,并了解我如何使用DataPart
函数-尽管您可以根据需要替换自己的Ron de Bruin's ISO week number function版本。
一些简短的注释:
Option Explicit
d
和Arr
的含义(即使现在看起来很明显)。这只是一个好习惯,并且可以使代码具有自说明性。代码模块:
Option Explicit
Sub w_test()
Dim initialDate As Date
Dim finaldate As Date
initialDate = #5/5/2015#
finaldate = #9/29/2017#
Dim weeks As Variant
weeks = WeekNumbers(initialDate, finaldate)
Debug.Print "There are " & UBound(weeks, 1) & " weeks between " & _
Format(initialDate, "dd-mmm-yyyy") & " and " & _
Format(finaldate, "dd-mmm-yyyy")
End Sub
Private Function WeekNumbers(ByVal initialDate As Date, _
ByVal finaldate As Date, _
Optional ByVal weekStart As VbDayOfWeek = vbSunday) As Variant
Dim numberOfWeeks As Long
numberOfWeeks = DateDiff("ww", initialDate, finaldate, weekStart, vbFirstFullWeek)
Dim startOfWeek As Date
If Weekday(initialDate) <> vbSunday Then
Dim adjustBy As Long
If Weekday(initialDate) > weekStart Then
adjustBy = Weekday(initialDate) - weekStart
Else
adjustBy = (Weekday(initialDate) + 7) - weekStart
End If
startOfWeek = DateAdd("d", -adjustBy, initialDate)
End If
Dim allTheWeeks As Variant
ReDim allTheWeeks(1 To numberOfWeeks)
Dim weekInfo As Variant
ReDim weekInfo(1 To 3)
Dim i As Long
For i = 1 To numberOfWeeks
weekInfo(1) = startOfWeek
weekInfo(2) = DatePart("ww", startOfWeek, weekStart, vbFirstFourDays)
weekInfo(3) = Year(startOfWeek)
allTheWeeks(i) = weekInfo
startOfWeek = DateAdd("ww", 1, startOfWeek)
Next i
WeekNumbers = allTheWeeks
End Function