Question

我想找到最灵活的方式来输出两个日期之间的周数列表。

例如：

输入

start = datetime.date(2011, 12, 25) 
end = datetime.date(2012, 1, 21)

输出

find_weeks(start, end)
>> [201152, 201201, 201202, 201203]

我一直在努力使用日期时间库而收效甚微

Answer 1

某些内容（更新：删除了不太可读的选项）

import datetime

def find_weeks(start,end):
    l = []
    for i in range((end-start).days + 1):
        d = (start+datetime.timedelta(days=i)).isocalendar()[:2] # e.g. (2011, 52)
        yearweek = '{}{:02}'.format(*d) # e.g. "201152"
        l.append(yearweek)
    return sorted(set(l))

start = datetime.date(2011, 12, 25) 
end = datetime.date(2012, 1, 21)

print(find_weeks(start,end)[1:]) # [1:] to exclude first week.

返回

['201152', '201201', '201202', '201203']

要包含第一周（201151），只需在函数调用后删除[1:]

Answer 2

private void Button1_Click(object sender, RoutedEventArgs e) { Style style = new Style { TargetType = typeof(Window) }; style.Setters.Add(new Setter(Window.BackgroundProperty, Brushes.Yellow)); Application.Current.Resources["MyStyle"] = style; }在这里是你的朋友 - 它会返回<Window x:Class="SimpleWpfPageApp.Window1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:local="clr-namespace:SimpleWpfPageApp" mc:Ignorable="d" Style="{DynamicResource MyStyle}"的元组。我们使用它将开始日期重置为每周开始，然后每次添加一周，直到我们通过结束日期：

.isocalendar()

打印

(year, week of year, day of week)

Answer 3

使用Pandas

import pandas as pd

dates=pd.date_range(start=start,end=end,freq='W')
date_index=dates.year.astype(str)+dates.weekofyear.astype(str).str.zfill(2)
date_index.tolist()

Answer 4

我建议您使用以下易于阅读的解决方案：

import datetime

start = datetime.date(2011, 12, 25) 
end = datetime.date(2012, 1, 21)

def find_weeks(start, end):
    l = []
    while (start.isocalendar()[1] != end.isocalendar()[1]) or (start.year != end.year):
        l.append(start.isocalendar()[1] + 100*start.year)
        start += datetime.timedelta(7)
    l.append(start.isocalendar()[1] + 100*start.year)
    return (l[1:])


print(find_weeks(start, end))

>> [201252, 201201, 201202, 201203]

使用python获取两个日期之间的周数

4 个答案: