我曾经相信在下面的语句中使用条件运算符是可以的,但事实并非如此。在复杂的语句中是否有任何限制条件使用条件运算符?
#include <iostream>
using namespace std;
int main() {
int a = 1;
int b = 10;
bool c = false;
int result = a * b + b + c ? b : a;
std::cout << result << std::endl;
return 0;
}
预测的输出:21
实际输出:10
为什么?
答案 0 :(得分:6)
此声明中的初始化程序
{
headers: {
/*...*/
},
user: /*...*/,
body: {
operationName: null,
variables: {},
query: 'mutation {\n login(data: {username: "admin", password: ' +
'"123456"}) {\n token\n id\n username\n isAdmin\n }\n' +
'}\n'
},
res: ServerResponse {
_events: [Object: null prototype] { finish: [Function: bound resOnFinish] },
_eventsCount: 1,
_maxListeners: undefined,
outputData: [],
outputSize: 0,
writable: true,
_last: false,
chunkedEncoding: false,
shouldKeepAlive: true,
useChunkedEncodingByDefault: true,
sendDate: true,
_removedConnection: false,
_removedContLen: false,
_removedTE: false,
_contentLength: null,
_hasBody: true,
_trailer: '',
finished: false,
_headerSent: false,
socket: Socket {
connecting: false,
_hadError: false,
_parent: null,
_host: null,
_readableState: [ReadableState],
readable: true,
_events: [Object],
_eventsCount: 8,
_maxListeners: undefined,
_writableState: [WritableState],
writable: true,
allowHalfOpen: true,
_sockname: null,
_pendingData: null,
_pendingEncoding: '',
server: [Server],
_server: [Server],
timeout: 120000,
parser: [HTTPParser],
on: [Function: socketOnWrap],
_paused: false,
_httpMessage: [Circular],
[Symbol(asyncId)]: 566,
[Symbol(kHandle)]: [TCP],
[Symbol(lastWriteQueueSize)]: 0,
[Symbol(timeout)]: Timeout {
/*...*/
},
[Symbol(kBytesRead)]: 0,
[Symbol(kBytesWritten)]: 0
},
connection: Socket {
connecting: false,
_hadError: false,
_parent: null,
_host: null,
_readableState: [ReadableState],
readable: true,
_events: [Object],
_eventsCount: 8,
_maxListeners: undefined,
_writableState: [WritableState],
writable: true,
allowHalfOpen: true,
_sockname: null,
_pendingData: null,
_pendingEncoding: '',
server: [Server],
_server: [Server],
timeout: 120000,
parser: [HTTPParser],
on: [Function: socketOnWrap],
_paused: false,
_httpMessage: [Circular],
[Symbol(asyncId)]: 566,
[Symbol(kHandle)]: [TCP],
[Symbol(lastWriteQueueSize)]: 0,
[Symbol(timeout)]: Timeout {
_idleTimeout: 120000,
_idlePrev: [TimersList],
_idleNext: [TimersList],
_idleStart: 3273,
_onTimeout: [Function: bound ],
_timerArgs: undefined,
_repeat: null,
_destroyed: false,
[Symbol(refed)]: false,
[Symbol(asyncId)]: 567,
[Symbol(triggerId)]: 566
},
[Symbol(kBytesRead)]: 0,
[Symbol(kBytesWritten)]: 0
},
_header: null,
_onPendingData: [Function: bound updateOutgoingData],
_sent100: false,
_expect_continue: false,
req: IncomingMessage {
/*...*/
},
locals: [Object: null prototype] {},
[Symbol(isCorked)]: false,
[Symbol(outHeadersKey)]: [Object: null prototype] {
'x-powered-by': [Array],
'access-control-allow-origin': [Array]
}
},
_extensionStack: GraphQLExtensionStack { extensions: [ [CacheControlExtension] ] }
}
等同于
int result = a * b + b + c ? b : a;
子表达式int result = ( a * b + b + c ) ? b : a;
的值为a * b + b + c
。由于它不等于0,因此会在上下文中转换为20
。
因此,条件表达式的值为第二个子表达式true
,它等于10。
我认为您的意思是声明中的以下初始化程序
b
答案 1 :(得分:4)
表达式a * b + b + c ? b : a
被分组为
(a * b + b + c) ? b : a
,表示结果为b
。还要注意,c
被隐式转换为值为int
的{{1}}。