Question

考虑以下数组// ------------ HOW TO MAKE THIS WORKING ??????????????? app.get('/project-2/*', (req, res) => { res.render('../project-2/index', { req }); });：

* installing *source* package 'burglr' ...
** using staged installation
Error in file(file, if (append) "a" else "w") : 
  (converti depuis l'avis) impossible d'ouvrir le fichier 
'C:/Users/Valirie/Documents/R/win-library/3.4/00LOCK- 
burglr/00new/burglr/DESCRIPTION' : No such file or directory
ERROR: installing package DESCRIPTION failed for package 'burglr'
* removing 'C:/Users/Valérie/Documents/R/win-library/3.4/burglr'

基于此数组，我想创建一个新的data = '''Venue : AmCham Office, 1 Scotts Rd, Shaw Centre #23-03 S(228208) - J&J Auditorium, Date : July 09, 2019, Time : 11:45 AM - 1:30 PM , Price : $25.00''' from bs4 import BeautifulSoup soup = BeautifulSoup(data, 'lxml') data = [] for p in soup.select('p'): data.append([d.strip() for d in p.text.split(':', 1)]) for (header, info) in data: print('{: <10}{: <60}'.format(header, info))，如下所示：

Venue     AmCham Office, 1 Scotts Rd, Shaw Centre #23-03 S(228208) - J&J Auditorium
Date      July 09, 2019                                               
Time      11:45 AM -  1:30 PM                                         
Price     $25.00

如您所见，这里的要求是只要'trackName'保持与下一个相同，就一直合并'url'的值，但是如果相同的“ trackName”应该存在于其他位置（例如在本示例中，我们有2倍的“ road-america”，但是由于两者之间存在不同的“ trackName”，因此不应将它们合并）。

到目前为止，我花了大量时间试图弄清楚如何到达那里（我想这必须使用嵌套循环吗？）

更新

这是我尝试过的事情之一（但是很明显，这只是看下一个'trackName'-不知道如何从这里继续）

$arr_sessions

Answer 1

不要查看下一个轨道名称，而是将上一次迭代中的轨道名称保存在变量中。每当它更改时，就在结果数组中开始一个新元素。

void*

Answer 2

这是带有输出的完整示例。您需要检查轨道名称是否与上一个相同，并相应地构建阵列。

$a = json_decode('[
  {
    "url": "2019_7_5_0_52_RACE.json",
    "trackName": "road-america"
  },
  {
    "url": "2019_7_5_0_27_RACE.json",
    "trackName": "road-america"
  },
  {
    "url": "2019_7_5_0_16_QUALIFY.json",
    "trackName": "road-america"
  },
  {
    "url": "2019_7_5_0_0_PRACTICE.json",
    "trackName": "road-america"
  },
  {
    "url": "2019_7_4_23_9_RACE.json",
    "trackName": "ttassen"
  },
  {
    "url": "2019_7_4_23_52_RACE.json",
    "trackName": "ttassen"
  },
  {
    "url": "2019_7_2_11_25_RACE.json",
    "trackName": "road-america"
  },
  {
    "url": "2019_7_2_11_03_RACE.json",
    "trackName": "road-america"
  }
]');

// Set previous track to null
$prev_track = NULL;
// New array
$new_a = [];
// Set counter
$i = 0;

foreach ($a as $value) {

  // If previous track name is different than current track name
  if ($prev_track !== $value->trackName) {

    // Increment counter
    $i++;
    // Create a new array entry
    $new_a[$i] = ['trackName' => $value->trackName, 'url' => [$value->url]];

  } else {
    // Append to previously created array entry
    $new_a[$i]['url'][] = $value->url;
  }

  // Set previous track to current track
  $prev_track = $value->trackName;
}

print json_encode(array_values($new_a));

这将输出：

[
  {
    "trackName": "road-america",
    "url": [
      "2019_7_5_0_52_RACE.json",
      "2019_7_5_0_27_RACE.json",
      "2019_7_5_0_16_QUALIFY.json",
      "2019_7_5_0_0_PRACTICE.json"
    ]
  },
  {
    "trackName": "ttassen",
    "url": [
      "2019_7_4_23_9_RACE.json",
      "2019_7_4_23_52_RACE.json"
    ]
  },
  {
    "trackName": "road-america",
    "url": [
      "2019_7_2_11_25_RACE.json",
      "2019_7_2_11_03_RACE.json"
    ]
  }
]

Answer 3

假设$ arr_sessions实际上是JSON，则可以尝试以下代码：

$output = [];
$data = json_decode($input);

foreach($data as $key=>$value) {
    if(isset($output[$value->trackName])) {
        array_push($output[$value->trackName]['url'], $value->url);
    } else {
        $output[$value->trackName] = [
            'trackName' => $value->trackName,
            'url' => [$value->url]
        ];
    }
}
$your_desired_format = array_values($output);

Answer 4

检查一下：

{
    "Version": "2012-10-17",
    "Statement": [{
        "Sid": "InvokeMyLambdaFunctionOnlyFromSNS",
        "NotPrincipal": {
            "Service": [
                "sns.amazon.com"
            ]
        },
        "Effect": "Deny",
        "Action": "lambda:InvokeFunction",
        "Resource": "arn:aws:lambda:region:AccountID:function:function_name"
    }]
}

基于键的PHP重新排序数组

更新

4 个答案: