Question

在仿真中我必须每秒计算汽车之间的距离，我的代码仅在时间= 0时显示

simulator :: schedule

double
 GetDistance_From (Ptr<Node> node1, Ptr<Node> node2)
{

  Ptr<MobilityModel> model1 = node1->GetObject<MobilityModel>();
  Ptr<MobilityModel> model2 = node2->GetObject<MobilityModel>();
  double distance = model1->GetDistanceFrom (model2);
 return distance;

}

并调用主函数

for (int i=0; i < 5; i++)
   {
     for (int k=i+1; k < 5; k++)
       {
          double dist= GetDistance_From(c.Get(i),c.Get(k));
         // Simulator::Schedule(Seconds(10), GetDistance_From,c.Get(i),c.Get(k), dist);
         int t = (Simulator::Now ()).GetSeconds ();

        std::ostringstream oss;
        oss  << "distance between Source Node(" << i << ") and Node(" <<k<<  ") est= " << dist<<" at time="<< t ;

       NS_LOG_UNCOND (oss.str());
       }
   }

结果仅一次

Answer 1

您必须将代码放入运行1000ms的循环中以模拟时间流逝。

Answer 2

只需重新组织代码并使用Simulator::Schedule()函数

void
 GetDistance_From (Ptr<Node> node1, Ptr<Node> node2, int i, int k)
{

  Ptr<MobilityModel> model1 = node1->GetObject<MobilityModel>();
  Ptr<MobilityModel> model2 = node2->GetObject<MobilityModel>();
  double distance = model1->GetDistanceFrom (model2);
  std::ostringstream oss;
  oss  << "distance between Source Node(" << i << ") and Node(" <<k<<  ") est= " << distance<<" at time="<< Simulator::Now().GetSeconds() ;
  NS_LOG_UNCOND (oss.str());

}

和main（）内-

for (int i=0; i < 5; i++)
   {
     for (int k=i+1; k < 5; k++)
       {
          double dist= GetDistance_From(c.Get(i),c.Get(k));
          Simulator::Schedule(Seconds(10), GetDistance_From,c.Get(i),c.Get(k),i,k);
       }
   }

计算每个时间实例的车辆节点的距离

2 个答案: