Question

我试图编写代码来旋转图像，我认为旋转图像的逻辑是正确的，但是每当我尝试显示旋转的图像时，都会出现以下错误：

TypeError：参数'mat'预期的cv :: UMat

我是python的新手，并且是第一次使用open cv，所以我对此并不了解

我检查了旋转图像的类型，它出现了“类'numpy.ndarray'”，我认为open cv可以在“ nd array”上工作

这是我的密码

import cv2
import numpy as np

def rotateToNinety(imageProcessing):
    imageProcessing = imageProcessing[::-1]
    rotatedImage = np.array([[[None for z in range(3)] for x in range(len(imageProcessing))]for y in range(len(imageProcessing[0]))])

    for i in range(len(imageProcessing[0])):
        for j in range(len(imageProcessing)):
            for k in range(3):
                rotatedImage[i][j][k] = imageProcessing[j][i][k]
    return rotatedImage


image = cv2.imread("download (2).jpg",1)

print("Original Image".center(50,"="))
print(image)

cv2.imshow("Original",image)
cv2.waitKey(0)

print(type(image))


rotated_90 = rotateToNinety(image)
print("Rotated Image".center(50,"="))
print(rotated_90)

print(type(rotated_90))
cv2.imshow("rotated",rotated_90)
cv2.waitKey(0)
cv2.destroyAllWindows()

Answer 1

我遇到了同样的问题并使用：

image=np.uint8(image)

图像是您的cv.imread（）对象。

Answer 2

您可以尝试更换

def rotateToNinety(imageProcessing):
    imageProcessing = imageProcessing[::-1]
    rotatedImage = np.array([[[None for z in range(3)] for x in range(len(imageProcessing))]for y in range(len(imageProcessing[0]))])

    for i in range(len(imageProcessing[0])):
        for j in range(len(imageProcessing)):
            for k in range(3):
                rotatedImage[i][j][k] = imageProcessing[j][i][k]
    return rotatedImage

到

def rotateToNinety(imageProcessing):
    h,w,c = imageProcessing.shape

    rotatedImage = np.zeros([h,w,c], dtype=np.uint8)

    imageProcessing = imageProcessing[::-1]

    for i in range(h):
        for j in range(w):
            for k in range(3):
                rotatedImage[i][j][k] = imageProcessing[j][i][k]
    return rotatedImage

在您的情况下，您将列与行混合在一起，请以后使用np.zeros()来定义空白图像。

Answer 3

通常，当您的图像路径错误时，可能会发生此错误。因此，您可能想再次检查图像路径。

TypeError：参数'mat'的预期cv :: UMat

3 个答案: