我正在尝试在同一行上从两个独立的元组打印两个独立的索引。但是当我使用f字符串打印时,它会将我打印的第二个索引放在新行上。
无论如何尝试,似乎都无法弄清楚,它总是在新行上打印姓氏。
surnames = tuple(open("Surnames.txt", "r"))
first_names_male = tuple(open("Male_names.txt", "r"))
first_names_female = tuple(open("Female_names.txt", "r"))
print(f"{first_names_male[0]} {surnames[0]}")
应全部打印出“ David Smith”
相反,它在第一行显示大卫,然后在下一行显示空格,然后是史密斯
答案 0 :(得分:1)
您可以使用如下代码从文件中每行的末尾删除新行并显式关闭文件:
with open("Surnames.txt", "r") as f:
surnames = f.read().splitlines()
with open("Male_names.txt", "r") as f:
first_names_male = f.read().splitlines()
with open("Female_names.txt", "r") as f:
first_names_female = f.read().splitlines()
print(f"{first_names_male[0]} {surnames[0]}")
或者如果您愿意,可以这样:
with open("Surnames.txt", "r") as f:
surnames = map(str.rstrip, f)
# or
surnames = [r.rstrip('\n') for r in f]
答案 1 :(得分:0)
这样可以更好地处理文件,因为它还会关闭文件并从每行末尾删除换行符。
def func(filename):
line_list = []
with open(filename) as f:
for line in f:
line = line.strip()
if len(line) > 0:
line_list.append(line)
return line_list
if __name__ == '__main__':
surnames_list = func('Surnames.txt')
male_names_list = func('Male_names.txt')
female_names_list = func('Female_names.txt')
print(f"{male_names_list[0]} {female_names_list[0]}")
这能给您想要的结果吗?