Question

我正在尝试运行以下代码，但由于SELECT语句中的最后一个字段同时包含汇总条件和正常条件而收到错误
trunc（d.ead_date）-trunc（max（d.pickup_date_ts））AS diff_ead_cpt_max

错误基本上是说GROUP BY子句中不允许聚合。如果我删除最大值，则可以使用，但是无法获得正确的结果。

SELECT
       w1.physical_country origin_country,
       a.leg_warehouse_id lm_warehouse_id,


       b.leg_warehouse_id fl_warehouse_id,


       c.plane_name,
       k.leg_ware,
       k.last_ds,

       trunc(a.ead_date) ead_date,
       max(d.pickup_date_ts) max_cpt,
       to_char(max(d.pickup_date_ts),'HH24:MI') max_cpt_time,
       trunc(max(d.pickup_date_ts)) max_cpt_date,
       trunc(d.ead_date)- trunc(max(d.pickup_date_ts)) AS diff_ead_cpt_max

from
       final_leg a 
       inner join dest_leg b 
       on a.shipment_id = b.shipment_id and a.route_id = b.route_id
       inner join sc_execution_eu.o_detailed_routes_v2 d 
       on a.shipment_id = d.shipment_id and a.route_id = d.route_id and d.leg_sequence_id = 0
       left join plane_leg c
       on a.shipment_id = c.shipment_id and a.route_id = c.route_id
       left join warehouse_attributes w1
       on a.route_warehouse_id = w1.warehouse_id
       left join warehouse_attributes w2
       on b.leg_warehouse_id = w2.warehouse_id
       RIGHT JOIN list_legs_ds k
       on a.route_warehouse_id = k.leg_ware AND a.leg_warehouse_id = k.last_ds


group by
       1,2,3,4,5,6,7,11

Answer 1

GROUP BY非汇总值，并使用列名：

SELECT
       w1.physical_country origin_country,
       a.leg_warehouse_id lm_warehouse_id,
       b.leg_warehouse_id fl_warehouse_id,
       c.plane_name,
       k.leg_ware,
       k.last_ds,
       trunc(a.ead_date) ead_date,
       max(d.pickup_date_ts) max_cpt,
       to_char(max(d.pickup_date_ts),'HH24:MI') max_cpt_time,
       trunc(max(d.pickup_date_ts)) max_cpt_date,
       trunc(d.ead_date)- trunc(max(d.pickup_date_ts)) AS diff_ead_cpt_max

from
       final_leg a 
       inner join dest_leg b 
       on a.shipment_id = b.shipment_id and a.route_id = b.route_id
       inner join sc_execution_eu.o_detailed_routes_v2 d 
       on a.shipment_id = d.shipment_id and a.route_id = d.route_id and d.leg_sequence_id = 0
       left join plane_leg c
       on a.shipment_id = c.shipment_id and a.route_id = c.route_id
       left join warehouse_attributes w1
       on a.route_warehouse_id = w1.warehouse_id
       left join warehouse_attributes w2
       on b.leg_warehouse_id = w2.warehouse_id
       RIGHT JOIN list_legs_ds k
       on a.route_warehouse_id = k.leg_ware AND a.leg_warehouse_id = k.last_ds
group by
       w1.physical_country origin_country,
       a.leg_warehouse_id lm_warehouse_id,
       b.leg_warehouse_id fl_warehouse_id,
       c.plane_name,
       k.leg_ware,
       k.last_ds,
       trunc(a.ead_date),
       trunc(d.ead_date)

Answer 2

您不能删除您已经说过的max，因为pickup_date_ts是未汇总的列，未列在GROUP BY列表中。

尝试trunc( max(trunc(d.ead_date) - d.pickup_date_ts))。

顺便说一句，不建议在GROUP BY表达式中使用列顺序号，SELECT列表中的某些更改可能会对它们产生不利影响，而应明确地写出列名。

在select语句中使用聚合时如何分组

2 个答案: