中断处理-执行C代码时出现“划分错误”

Question

SELECT MIN(p.start_date), CONCAT(c.first_name, ' ', c.last_name) AS 'c.fullname', c.temp_nr
FROM contactstable c 
LEFT JOIN projectlines p on c.temp_nr = p.candidate_number 
WHERE c.temp_nr ='XXXX' and c.contact_type = 'Candidate' 
HAVING MIN(p.start_date) between DATE_SUB( CURDATE( ) , INTERVAL (dayofweek(CURDATE())+6) 
DAY ) 
AND DATE_SUB( CURDATE( ) , INTERVAL (dayofweek(CURDATE())) 
DAY )

//计算释放第一个字符和设置第二个字符之间的频率，

#include <stdio.h>
#include <dos.h>
#include<stdlib.h>

//从最高索引开始，以避免堆栈崩溃

volatile int stopper = 0;
volatile int index = 3;

//挡块将计数时间，介于上一次释放时间和向上按动键之间

volatile int diff1[4] = {0,0,0,0}; 
volatile int diff2[4] = { 0,0,0,0 }; 
volatile int gotChar = 0;//to know in if I got in the same time new char 
volatile int secondW =0; //to know if the first word ended void 
interrupt(*Int8save)(void);

 /////////////////////////////////////////////////////////////// 

void interrupt myhandle() {     
     inputFlag = 1;     
     if (index == 0 && secondW ==1)  { index = -1;  return; }   
     if (index == 0 && secondW == 0)
         { printf("\nNow AGAIN\n"); index =3;}
     if (secondW == 1 && index <2) { diff2[3 - index] = stopper; }  
     else if (index < 2) { diff1[3 -index] = stopper; }
     stopper = 0;
     Int8Save();
     if (index > 0)
            index--;
     while(gotChar == 0)stopper++;