我具有以下数据集的大版本。
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bundler: failed to load command: fastlane (/usr/local/bin/fastlane)
FastlaneCore::Interface::FastlaneCrash: [!] Could not retrieve response as fastlane runs in non-interactive mode
/Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane_core/lib/fastlane_core/ui/interface.rb:129:in crash!' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane_core/lib/fastlane_core/ui/implementations/shell.rb:155:in verify_interactive!'
/Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane_core/lib/fastlane_core/ui/implementations/shell.rb:133:in confirm' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane_core/lib/fastlane_core/ui/ui.rb:17:in method_missing'
/Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane/lib/fastlane/commands_generator.rb:343:in ensure_fastfile' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane/lib/fastlane/commands_generator.rb:107:in block (2 levels) in run'
/Library/Ruby/Gems/2.3.0/gems/commander-fastlane-4.4.6/lib/commander/command.rb:178:in call' /Library/Ruby/Gems/2.3.0/gems/commander-fastlane-4.4.6/lib/commander/command.rb:153:in run'
/Library/Ruby/Gems/2.3.0/gems/commander-fastlane-4.4.6/lib/commander/runner.rb:476:in run_active_command' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane_core/lib/fastlane_core/ui/fastlane_runner.rb:76:in run!'
/Library/Ruby/Gems/2.3.0/gems/commander-fastlane-4.4.6/lib/commander/delegates.rb:15:in run!' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane/lib/fastlane/commands_generator.rb:333:in run'
/Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane/lib/fastlane/commands_generator.rb:41:in start' /Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/fastlane/lib/fastlane/cli_tools_distributor.rb:119:in take_off'
/Library/Ruby/Gems/2.3.0/gems/fastlane-2.126.0/bin/fastlane:23:in <top (required)>' /usr/local/bin/fastlane:22:in load'
/usr/local/bin/fastlane:22:in `<top (required)>'
Exited with code 1
我希望将前两行组合在一起,以便得到的数据集看起来像这样
mydata <- data.frame("C1" = c("EB", "L", 1, 2, 3) ,
"C2" = c("WB", "T", 4, 5, 6),
"C3" = c("NB", "R", 7, 8, 9),
"C4" = c("SB", "Total", 12, 15, 18),
"C5" = c("", "L",1, 2, 3),
"C6" = c("", "TR", 4, 5, 6),
"C7" = c("", "Total", 5, 7, 9),
"C8" = c("", "L",1, 2, 3),
"C9" = c("", "R", 4, 5, 6),
"C10" = c("", "Total", 5, 7, 9),
"C11" = c("", "L",1, 2, 3),
"C12" = c("", "TR", 4, 5, 6),
"C13" = c("", "Total", 5, 7, 9), stringsAsFactors = FALSE)
> mydata
C1 C2 C3 C4 C5 C6 C7 C8 C9 C10 C11 C12 C13
1 EB WB NB SB
2 L T R Total L TR Total L R Total L TR Total
3 1 4 7 12 1 4 5 1 4 5 1 4 5
4 2 5 8 15 2 5 7 2 5 7 2 5 7
5 3 6 9 18 3 6 9 3 6 9 3 6 9
基本上,我想保留其余的数据框。
请注意:这种情况来自具有1000条记录和18个列的非常大的数据集。任何帮助都感激不尽。预先感谢!
更新: 我尝试过
> myresult
C1 C2 C3 C4 C5 C6 C7 C8 C9 C10 C11 C12 C13
1 EBL EBT EBR EBTotal WBL WBTR WBTotal NBL NBR NBTotal SBL SBTR SBTotal
2 1 4 7 12 1 4 5 1 4 5 1 4 5
3 2 5 8 15 2 5 7 2 5 7 2 5 7
4 3 6 9 18 3 6 9 3 6 9 3 6 9
但这只是从第一行重复一个值
mydata[1,]= paste0(rep(mydata[1,], each = length(mydata[2,])), mydata[2,])
答案 0 :(得分:2)
查看数据,您似乎想要将第一行组合粘贴到第二行,直到值<input type="text" id="inputName" placeholder="Enter name" required oninvalid="this.setCustomValidity('Your Message')" oninput="this.setCustomValidity('') />
进入第二行。我们可以分别提取第一行和第二行,根据"Total"
的出现split
对其进行粘贴,然后将其粘贴到"Total"
以获得新值。
first_row
答案 1 :(得分:1)
您必须重复“ EB”四次,其他仅重复三遍。我认为现在是正确的:
colnames(mydata) <- paste0(c(rep(mydata[1,1], 4), rep(mydata[1, 2:4], each = 3)), mydata[2,])
mydata2 <- apply(mydata[-c(1:2),], 2, as.numeric)
> mydata2
EBL EBT EBR EBTotal WBL WBTR WBTotal NBL NBR NBTotal SBL SBTR SBTotal
[1,] 1 4 7 12 1 4 5 1 4 5 1 4 5
[2,] 2 5 8 15 2 5 7 2 5 7 2 5 7
[3,] 3 6 9 18 3 6 9 3 6 9 3 6 9